Question

尝试使用Jquery及其失败警报Not connect使用django tastypie创建多个对象，如下面的代码所示。但使用相同的数据（sent_data）执行curl请求传递给ajax，效果很好。

sent_data = {"objects":[{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]},{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]}]};

$.ajax({
        type:'POST',
        url:'http://localhost:8000/api/v1/order/',
        contentType: 'application/json',
        data:sent_data,
        headers:{'X-HTTP-Method-Override':'PATCH'},
        dataType:'json',
        processData:false,
        success: function(data){
            alert("POST request made");

        },
        error: function(jqXHR,exception){
            if (jqXHR.status === 0) {
                alert('Not connect.\n Verify Network.');
            } else if (jqXHR.status == 404) {
                alert('Requested page not found. [404]');
            } else if (jqXHR.status == 500) {
                alert('Internal Server Error [500].');
            } else if (exception === 'parsererror') {
                alert('Requested JSON parse failed.');
            } else if (exception === 'timeout') {
                alert('Time out error.');
            } else if (exception === 'abort') {
                alert('Ajax request aborted.');
            } else {
                alert('Uncaught Error.\n' + jqXHR.responseText);
            }
        }
    });

看着django-tastypie PATCH gives me a "400 (Bad Request)"和Ajax Post Request to TastyPie Doesn't Do Anything，因为我正在尝试按照文档中的说法进行批量操作，我不得不使用'PATCH'方法，我通过提供X-HTTP来实现-Method-Override标题但都是徒劳的。我能错过什么？

Answer 1

在做了更多的研究后，我发现问题是我没有为表单中的'CSRFToken'设置标题，这个要点here帮助我解决了问题。所以工作请求看起来如此，

sent_data = JSON.stringify({"objects":[{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]},{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]}]});

$.ajax({
        url:'/api/v1/order/?format=json',
        accepts:'application/json',
        contentType: 'application/json',
        headers:{
            'X-HTTP-Method-Override':'PATCH'
        },
        method:'POST',
        data:sent_data,
        beforeSend:function(jqXHR,settings){
            jqXHR.setRequestHeader('X-CSRFToken',$("input[name=csrfmiddlewaretoken]").val())
        },
        dataType:'json',
        processData:false,
        success: function(data){
            alert("damn posted");

        },
        error: function(jqXHR,exception){
            if (jqXHR.status === 0) {
                alert('Not connect.\n Verify Network.');
            } else if (jqXHR.status == 404) {
                alert('Requested page not found. [404]');
            } else if (jqXHR.status == 500) {
                alert('Internal Server Error [500].');
            } else if (exception === 'parsererror') {
                alert('Requested JSON parse failed.');
            } else if (exception === 'timeout') {
                alert('Time out error.');
            } else if (exception === 'abort') {
                alert('Ajax request aborted.');
            } else {
                alert('Uncaught Error.\n' + jqXHR.responseText);
            }
        }
    });

另请注意我传递给JSON.stringify（）方法。

如何使用PATCH方法通过Ajax使用django tastypie创建多个对象？

1 个答案: