我需要为Android制作一个简单的应用程序,每隔25秒将智能手机的位置发送到Web应用程序。我的网络应用程序在线,现在我可以像这样手动传递值:
http://mywebapp.com/coordinates/create?latitude=18.463108&longitude=-69.929117
我是Android开发的绝对初学者,所以请尝试一步一步地解释我。
答案 0 :(得分:8)
经过深入研究后,我发现我认为最简单的方法是在查询字符串中发送GPS位置(纬度,经度)。也许网上没有比此更短的代码。所以我们将分两步完成:
首先将此权限添加到AndroidManifest.xml
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
现在,您在MainActivity.java
内的代码public class MainActivity extends Activity { }
public class MainActivity extends Activity {
public double latitude;
public double longitude;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
/* Use the LocationManager class to obtain GPS locations */
LocationManager mlocManager = (LocationManager)getSystemService(Context.LOCATION_SERVICE);
LocationListener mlocListener = new MyLocationListener();
mlocManager.requestLocationUpdates( LocationManager.GPS_PROVIDER, 0, 0, mlocListener);
}
/* Class My Location Listener */
public class MyLocationListener implements LocationListener {
@Override
public void onLocationChanged(Location loc) {
latitude = loc.getLatitude();
longitude = loc.getLongitude();
String Text = "My current Latitude = " + latitude + " Longitude = " + longitude;
Toast.makeText( getApplicationContext(),Text,Toast.LENGTH_SHORT).show();
SendQueryString(); // for send the Query String of latitude and logintude to the webapp.
}
@Override
public void onProviderDisabled(String provider) {
Toast.makeText( getApplicationContext(),"Gps Disabled",Toast.LENGTH_SHORT ).show();
}
@Override
public void onProviderEnabled(String provider) {
Toast.makeText( getApplicationContext(),"Gps Enabled",Toast.LENGTH_SHORT).show();
}
@Override
public void onStatusChanged(String provider, int status, Bundle extras) {
}
}/* End of Class MyLocationListener */
public void SendQueryString() {
new Thread() {
public void run() {
String url = "http://mywebapp.com/coordinates/create?latitude=" + latitude +"&longitude=" + longitude;
try {
HttpClient Client = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
Client.execute(httpget);
}
catch(Exception ex) {
String fail = "Fail!";
Toast.makeText( getApplicationContext(),fail,Toast.LENGTH_SHORT).show();
}
}
}.start();
}
}
注意:正如您所看到的,我在函数new Thread() { public void run() {/*code here*/}}.start();
中使用SendQueryString()
,这是因为我们正在尝试向服务器发出请求,所以在Android无法向主体线程中的服务器发出请求,其中图形和主体进程是。实际上,如果您尝试在主线程中发出请求,它将返回错误。
答案 1 :(得分:0)
首先到达位置:
LocationManager locMan = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
locMan.requestLocationUpdates(
LocationManager.GPS_PROVIDER, 0, 0, location listener);
第一个零表示位置更新的时间间隔 第二个代表更新的距离间隔..配置就像你一样。
在听众中:
public void onLocationChanged(Location location) {
if (location != null) {
double lat = location.getLatitude();
double long = location.getLongitude();
}
}
您只需要使用该链接发出http请求,如下所示:
String url = "http://mywebapp.com/coordinates/createlatitude=" + lat +"&longitude=" + long;
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
httpClient.execute(httpGet);