希望我在这里有一个简单的问题,并以正确的方式向您解释。
我有以下查询:
--DECLARE DATES
DECLARE @Date datetime
DECLARE @DaysInMonth INT
DECLARE @i INT
--GIVE VALUES
SET @Date = Getdate()
SELECT @DaysInMonth = datepart(dd,dateadd(dd,-1,dateadd(mm,1,cast(cast(year(@Date) as varchar)+'-'+cast(month(@Date) as varchar)+'-01' as datetime))))
SET @i = 1
--MAKE TEMP TABLE
CREATE TABLE #TempDays
(
[days] VARCHAR(50)
)
WHILE @i <= @DaysInMonth
BEGIN
INSERT INTO #TempDays
VALUES(@i)
SET @i = @i + 1
END
SELECT #TempDays.days, DATEPART(dd, a.ActualDate) ActualDate, a.ActualAmount, (SELECT SUM(b.ActualAmount)
FROM UnpaidManagement..Actual b
WHERE b.ID <= a.ID) RunningTotal
FROM UnpaidManagement..Actual a
RIGHT JOIN #TempDays on a.ID = #TempDays.days
DROP TABLE #TempDays
产生以下输出:
+------+------------+--------------+--------------+
| days | ActualDate | ActualAmount | RunningTotal |
+------+------------+--------------+--------------+
| 1 | 1 | 438706 | R 438 706 |
| 2 | 2 | 16239 | R 454 945 |
| 3 | 3 | 1611264 | R 2 066 209 |
| 4 | 4 | 1157777 | R 3 223 986 |
| 5 | 5 | 470662 | R 3 694 648 |
| 6 | 6 | 288628 | 3983276 |
| 7 | 7 | 245897 | 4229173 |
| 8 | 8 | 5235 | 4234408 |
| 9 | 10 | 375630 | 4610038 |
| 10 | 11 | 95610 | 4705648 |
| 11 | 12 | 87285 | 4792933 |
| 12 | 13 | 73399 | 4866332 |
| 13 | 14 | 59516 | 4925848 |
| 14 | 15 | 918915 | 5844763 |
| 15 | 17 | 1957285 | 7802048 |
| 16 | 18 | 489964 | 8292012 |
| 17 | 19 | 272304 | 8564316 |
| 18 | 20 | 378601 | 8942917 |
| 19 | 22 | 92374 | 9035291 |
| 20 | 23 | 198 | 9035489 |
| 21 | 24 | 1500820 | 10536309 |
| 22 | 25 | 2631057 | 13167366 |
| 23 | 26 | 6466505 | 19633871 |
| 24 | 27 | 3757350 | 23391221 |
| 25 | 28 | 3487466 | 26878687 |
| 26 | 29 | 160197 | 27038884 |
| 27 | 30 | 14000 | 27052884 |
| 28 | NULL | NULL | NULL |
| 29 | NULL | NULL | NULL |
| 30 | NULL | NULL | NULL |
| 31 | NULL | NULL | NULL |
+------+------------+--------------+--------------+
如果仔细查看上表,“ActualDate”列缺少一些值,EG:9,16等。
正因为如此,行被推高而不是按正确的数字分组?我如何通过/任何方式完成一组以使它们保持正确的行?
期望的输出:
+------+------------+--------------+--------------+
| days | ActualDate | ActualAmount | RunningTotal |
+------+------------+--------------+--------------+
| 1 | 1 | 438706 | R 438 706 |
| 2 | 2 | 16239 | R 454 945 |
| 3 | 3 | 1611264 | R 2 066 209 |
| 4 | 4 | 1157777 | R 3 223 986 |
| 5 | 5 | 470662 | R 3 694 648 |
| 6 | 6 | 288628 | 3983276 |
| 7 | 7 | 245897 | 4229173 |
| 8 | 8 | 5235 | 4234408 |
| 9 | NULL | NULL | NULL |
| 10 | 10 | 375630 | 4610038 |
| 11 | 11 | 95610 | 4705648 |
| 12 | 12 | 87285 | 4792933 |
| 13 | 13 | 73399 | 4866332 |
| 14 | 14 | 59516 | 4925848 |
| 15 | 15 | 918915 | 5844763 |
| 16 | NULL | NULL | NULL |
| 17 | 17 | 1957285 | 7802048 |
| 18 | 18 | 489964 | 8292012 |
| 19 | 19 | 272304 | 8564316 |
| 20 | 20 | 378601 | 8942917 |
| 21 | NULL | NULL | NULL |
| 22 | 22 | 92374 | 9035291 |
| 23 | 23 | 198 | 9035489 |
| 24 | 24 | 1500820 | 10536309 |
| 25 | 25 | 2631057 | 13167366 |
| 26 | 26 | 6466505 | 19633871 |
| 27 | 27 | 3757350 | 23391221 |
| 28 | 28 | 3487466 | 26878687 |
| 29 | 29 | 160197 | 27038884 |
| 30 | 30 | 14000 | 27052884 |
| 31 | NULL | NULL | NULL |
+------+------------+--------------+--------------+
我知道这是一个很长的阅读,但如果我已经清楚地解释了这一点,请告诉我。我整个上午一直试图分组,但我一直都有错误。
答案 0 :(得分:1)
SELECT #TempDays.days, DATEPART(dd, a.ActualDate) ActualDate, a.ActualAmount, (SELECT SUM(b.ActualAmount)
FROM UnpaidManagement..Actual b
WHERE b.ID <= a.ID) RunningTotal
FROM UnpaidManagement..Actual a
RIGHT JOIN #TempDays on DATEPART(dd, a.ActualDate) = #TempDays.days
答案 1 :(得分:0)
如果您选择临时表作为选择中的第一个表并加入UnpaidManagement..Actual
,那么您的日期将按正确的行和顺序排列:
SELECT t.days
,DATEPART(dd, a.ActualDate) ActualDate
,a.ActualAmount
,(
SELECT SUM(b.ActualAmount)
FROM UnpaidManagement..Actual b
WHERE b.ID <= a.ID
) RunningTotal
FROM #TempDays AS t
INNER JOIN UnpaidManagement..Actual AS a ON a.IDENTITYCOL = t.days
ORDER BY t.days
完成此操作后,cou可以添加CASE WHEN
以生成NULL
单元格的内容。