Question

编辑：抱歉取消的是数据库中的tinyint类型我有一个带有1个复选框的表单 - 我希望它在检查时更新我的数据库以显示课程被取消。默认情况下，我的数据库中的值为0，但是当我尝试更新课程以取消它时，值永远不会更改为1.请帮忙！

这是我的editForm代码段：

  <p><label class="field" for "Credits">Credits:</label>                      <input type="text" name="cred" size="40" value="<?php echo "$row[Credits]"?>" class="rep"></p>
             <p><label class="field" for "Cancelled">Cancelled:</label>      (Tick to cancel)   <input type="checkbox" name="canc" size="40" value="Yes" class="rep"></p>
            <input type="submit" name="submit_value" value="Update"></p>

这是我的updateCourse php页面：

$id = $_POST["id"];

$title = $_POST["title"];
$cat = $_POST["cat"];
$loc = $_POST["loc"];
$county = $_POST["county"];
$time = $_POST["time"];
$date = $_POST["date"];
$cred = $_POST["cred"];
$fac = $_POST["fac"];

$canc = $_POST["canc"];

if(isset($_POST['submit_value'])) {

if(isset($_POST['canc'])) {
    $canc = isset($_POST['canc']) ? '1' : '0';
    $query1 = "UPDATE Course 
        SET Title = '$title',
            Category = '$cat',
            Location = '$loc',
            County = '$county',
            Course_Time = '$time',
            Course_Date = '$date',
            Credits = '$cred',
            Facilitator = '$fac'
            Cancelled = '$canc'
            WHERE CourseID = '$id' ";
    $result = $mysqli_db->query($query1);

}   else {      

    $query2 = "UPDATE Course 
        SET Title = '$title',
            Category = '$cat',
            Location = '$loc',
            County = '$county',
            Course_Time = '$time',
            Course_Date = '$date',
            Credits = '$cred',
            Facilitator = '$fac'

        WHERE CourseID = '$id' ";

$query_result = $mysqli_db->query($query2);

我的query2正在运行，但query1从不更改我的数据库中的已取消值

Answer 1

您在查询中缺少此行中字段之间的逗号：

Facilitator = '$fac'

之后应该有一个逗号：

$query1 = "UPDATE Course 
    SET Title = '$title',
        Category = '$cat',
        Location = '$loc',
        County = '$county',
        Course_Time = '$time',
        Course_Date = '$date',
        Credits = '$cred',
        Facilitator = '$fac',
        Cancelled = '$canc'
         WHERE CourseID = '$id' ";

这会触发MySQL错误。您可以使用mysql_error()来调试这些问题。回显或打印查询通常也有助于发现错误。

http://php.net/manual/en/function.mysql-error.php

Answer 2

首先，简单代码行太多了。您正在重复$canc的发起。如果你用0和1分配变量，为什么heck 2会查询？ 1更简单，更易读。此外，您可以更轻松地进行调试。其次，您需要了解PDO语句或过滤，因为您的脚本非常容易受到攻击。例如，您的脚本可以缩短为：

$canc = isset($_POST['canc']) ? '1' : '0';

if(isset($_POST['submit_value'])) {
    $query = "
        UPDATE Course 
        SET Title = '$title',
            Category = '$cat',
            Location = '$loc',
            County = '$county',
            Course_Time = '$time',
            Course_Date = '$date',
            Credits = '$cred',
            Facilitator = '$fac',
            Cancelled = '$canc'
        WHERE CourseID = '$id'";
    $query_result = $mysqli_db->query($query);      
}

复选框勾选时数据库不更新

2 个答案: