Question

我有一个简单的搜索小部件，我很难在我的应用程序中实现自定义搜索建议功能。

关于＆＃34; Building a suggestion table＆＃34;的Google Api文档记录真的很糟糕。到目前为止，我已经设法获得我的＆＃34; SearchContentProvider＆＃34;工作，返回建议，但当我输入下拉菜单时，我只得到＆＃34;空白＆＃34;字段，没有文字。

有人可以建议我如何构建建议表吗？我应该在哪里实施＆＃34; SUGGEST_COLUMN_TEXT_1＆＃34;为了格式化并得到我的建议吗？

enter image description here

SearchContentProvider.java：

package com.exploreca.tourfinder;

import android.content.ContentProvider;
import android.content.ContentValues;

import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

import android.net.Uri;
import android.util.Log;

public class SearchContentProvider extends ContentProvider {

    SQLiteOpenHelper dbhelper;
    SQLiteDatabase database;        
    Cursor cursor; 
    private String LOGTAG;


    @Override
    public int delete(Uri arg0, String arg1, String[] arg2) {
        // TODO Auto-generated method stub
        return 0;
    }

    @Override
    public String getType(Uri arg0) {
        // TODO Auto-generated method stub
        return null;
    }

    @Override
    public Uri insert(Uri arg0, ContentValues arg1) {
        // TODO Auto-generated method stub
        return null;
    }

    @Override
    public boolean onCreate() {
        // TODO Auto-generated method stub
        return false;
    }

    @Override
    public Cursor query(Uri uri, String[] projection, String selection, 
              String[] selectionArgs, String sortOrder) { 

        //instantieting the datasouce
        dbhelper = new ToursDBOpenHelper(getContext());
        database = dbhelper.getReadableDatabase();
        Log.i(LOGTAG, "Selection Args: " + selectionArgs[0] + "\n " + "selection is: " + selection);        

        cursor = database.query(ToursDBOpenHelper.TABLE_TOURS, null, 
                selection, selectionArgs, null, null, null);

        Log.i(LOGTAG, "Returned" + cursor.getCount() + "rows");

        if (cursor.getCount() > 0){
            while(cursor.moveToNext()){         

                cursor.getColumnIndex(cursor.getString(cursor.getColumnIndex(ToursDBOpenHelper.COLUMN_CITY)));
                Log.i(LOGTAG, "Cursor is" + cursor);
            }           
        } 
            return cursor;      
    }


    @Override
    public int update(Uri arg0, ContentValues arg1, String arg2, String[] arg3) {
        // TODO Auto-generated method stub
        return 0;
    }

}

Answer 1

如果您仍在寻找解决方案，则需要使用SearchManager.SUGGEST_COLUMN_TEXT_1而不是SUGGEST_COLUMN_TEXT_1作为said in this answer。

Answer 2

我已经弄清楚了。即使我添加了＆＃34; SUGGEST_COLUMN_TEXT_1＆＃34;作为我桌子的新栏目，无论我把它放进去，它都是空的。

所以我从数据库表中删除了它，并以HashMap的形式将其添加到我的ContentProvider中，HashMap由一组键和值对组成。在HashMap中，每个键都映射到一个值。

我已经花了几天时间搞清楚这一点，希望用工作代码帮助其他人：

...

    @Override
    public Cursor query(Uri uri, String[] projection, String selection, 
                  String[] selectionArgs, String sortOrder) { 

                SQLiteQueryBuilder builder = new SQLiteQueryBuilder();
                builder.setTables(ToursDBOpenHelper.TABLE_TOURS);

                HashMap<String, String> columnMap = new HashMap<String, String>();
                columnMap.put(BaseColumns._ID, ToursDBOpenHelper.COLUMN_ID + " AS " + BaseColumns._ID);
                columnMap.put(SearchManager.SUGGEST_COLUMN_TEXT_1, ToursDBOpenHelper.COLUMN_TITLE + " AS " + SearchManager.SUGGEST_COLUMN_TEXT_1);
                columnMap.put(SearchManager.SUGGEST_COLUMN_INTENT_DATA, ToursDBOpenHelper.COLUMN_ID + " AS " + SearchManager.SUGGEST_COLUMN_INTENT_DATA);
                builder.setProjectionMap(columnMap);

                dbhelper = new ToursDBOpenHelper(getContext());
                //database = dbhelper.getReadableDatabase();

                SQLiteDatabase db = dbhelper.getWritableDatabase();
                cursor = builder.query(db, projection, selection, selectionArgs, null, null, sortOrder, null);

                return cursor;
        }

...

空/空白下拉，android自定义搜索建议

2 个答案: