Question

我正在检查并查看我的2d阵列tic tac toe board是否仅包含x和o，但是我不知道如何做到这一点。这是给我的代码......

#include <cstdlib>
#include <iostream>
using namespace std;

int main()
{
   // Declare 2D array
   const int SIZE = 3;
   char board[SIZE][SIZE];

   // Read x's and o's
   cout << "Enter x's and o's on board (L-R, T-B): ";
   for (int r = 0; r < SIZE; r++)
      for (int c = 0; c < SIZE; c++)
         cin >> board[r][c];

   // Print 2D array
   cout << "\n+---+---+---+\n";
   for (int r = 0; r < SIZE; r++)
   {
      cout << "| ";
      for (int c = 0; c < SIZE; c++)
         cout << board[r][c] << " | ";
      cout << "\n+---+---+---+\n";
   }

   // Check board contains only x's and o's
   bool valid = true;
   // TBA
   if (!valid)
   {
      cout << "Sorry, you can only enter x's and o's\n";
      exit(1);
   }

Answer 1

只需在数组上循环并检查每个：

for(int i = 0; i < SIZE; i++)
  for(int j = 0; j < SIZE; j++)
    if(board[i][j] != 'x' and board[i][j] != 'o')
      valid = false;

但最好尽早进行数据验证，例如直接输入。

Answer 2

你可以迭代整个董事会，如下：

for(int r = 0; r < SIZE; r++){
    for(int c = 0; c < SIZE; c++){
        // some validation code
    }
}

但更好的解决方案可能是在输入字符时对其进行验证：

for(int r = 0; r < SIZE; r++){
    for(int c = 0; c < SIZE; c++){
        char in = 'a';
        while(in != 'x' || in != 'o'){
            cin >> in;
        }
    }
}

除了您想要给用户的任何有用的反馈

Answer 3

#include <algorithm>
#include <iterator>

//,,,

bool valid = std::all_of( std::begin( board ), std::end( board ),
    [=]( const char ( &row )[SIZE] )
    {
        return std::all_of( std::begin( row ), std::end( row ),
            []( char c ) { return ( c == 'x' || c == 'o' ); } );
    } );

例如

#include <iostream>
#include <iomanip>
#include <algorithm>
#include <iterator>


int main()
{
    const int SIZE = 3;
    char board[SIZE][SIZE] = { { 'x', 'x', 'o' }, { 'o', 'x', 'o' }, { 'o', 'x', 'x' } };

    bool valid = std::all_of( std::begin( board ), std::end( board ),
        [=]( const char ( &row )[SIZE] )
        {
            return std::all_of( std::begin( row ), std::end( row ),
                []( char c ) { return ( c == 'x' || c == 'o' ); } );
        } );

    std::cout << std::boolalpha << is_valid << std::endl;
}

我正在使用默认捕获[=]因为据我所知MS VC ++有一个错误。

你可以阅读here 虽然它是用俄语写的，但您可以使用在线工具将其翻译成英语，例如谷歌翻译。

检查2d tic tac toe数组位置c ++

3 个答案: