Question

我的数据库中有这些表：

USER_ACCOUNT
USER_CHARACTER

USER_ACCOUNT列：AccountID，Character1，Character2，Character3

USER_CHARACTER列：它包含特定字符的所有数据   单独但在这种特定情况下我们需要列UserID和   SpecialPoints。

那么，如何通过提供character1,character2 and character3 from USER_ACCOUNT抓住所有AccountID并检查其中哪一个>50000 SpecialPoints from USER_CHARACTER？

如果发现其中一个字符为>50000 SpecialPoints，则更新特定字符并删除-50000 SpecialPoints。

我将在我的php脚本上创建两个检查但我仍然坚持创建实际的查询。

我正在使用 MSSQL Server 2005

Answer 1

好吧，我会抓住它，希望我理解这些问题，但更有可能提供帮助澄清的基础。

注意：我假设USER_ACCOUNT.Character1例如是USER_CHARACTER中的某个FK。应该是。

有几种方法可以帮助您入门。

首先是一些样本数据：

CREATE TABLE USER_ACCOUNT (AccountID INT, Character1 INT,Character2 INT,Character3 INT)
CREATE TABLE USER_CHARACTER (CharacterID INT, SpecialPoints INT)
GO

INSERT INTO USER_ACCOUNT VALUES (1,10,20,30),(2,40,50,60)
INSERT INTO USER_CHARACTER VALUES (10,10000),(20,20000),(30,30000),(40,40000),(50,50000),(60,60000)

GO

选项1将多次加入。

SELECT Character1
      ,c1.SpecialPoints
      ,CASE WHEN c1.SpecialPoints > 50000 THEN 1 ELSE 0 END Character1_50000PlusPoints
      ,Character2
      ,c2.SpecialPoints
      ,CASE WHEN c2.SpecialPoints > 50000 THEN 1 ELSE 0 END Character2_50000PlusPoints
      ,Character3
      ,c3.SpecialPoints
      ,CASE WHEN c2.SpecialPoints > 50000 THEN 1 ELSE 0 END Character3_50000PlusPoints
  FROM            USER_ACCOUNT a
        LEFT JOIN USER_CHARACTER c1 ON a.Character1 = c1.CharacterID
        LEFT JOIN USER_CHARACTER c2 ON a.Character2 = c2.CharacterID
        LEFT JOIN USER_CHARACTER c3 ON a.Character3 = c3.CharacterID

GO

选项2将使用UNION

WITH cte AS (
  SELECT AccountID
        ,CharacterID
        ,SpecialPoints
    FROM USER_ACCOUNT a
         INNER JOIN 
         USER_CHARACTER b ON a.Character1 = b.CharacterID
    UNION ALL
  SELECT AccountID
        ,CharacterID
        ,SpecialPoints
    FROM USER_ACCOUNT a
         INNER JOIN 
         USER_CHARACTER b ON a.Character2 = b.CharacterID
    UNION ALL
  SELECT AccountID
        ,CharacterID
        ,SpecialPoints
    FROM USER_ACCOUNT a
         INNER JOIN 
         USER_CHARACTER b ON a.Character3 = b.CharacterID
)
SELECT *
  FROM cte
 WHERE SpecialPoints > 50000

我被困在一些sql server查询

1 个答案: