Question

//我想在列表视图中显示列表项我将所有项放在列表中我想显示它正在显示的列表视图中的所有项目，但获取相同的名称，我在getview中保持for循环。请帮助我如何在列表视图中显示列表项。

public class Listjava extends Activity {
    /** Called when the activity is first created. */
    int i = 0;
    List<Contact> contacts;
    MyBaseAdapter adapter;
    final DatabaseHandler db = new DatabaseHandler(this);

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.layout);
        contacts = db.getAllContacts();
        ListView list = (ListView) findViewById(R.id.listView1);
        adapter = new MyBaseAdapter(getApplicationContext(), contacts);
        list.setAdapter(adapter);
    }

    public class MyBaseAdapter extends BaseAdapter {

        private LayoutInflater inflater = null;

        public MyBaseAdapter(Context applicationContext, List<Contact> contacts) {
            // TODO Auto-generated constructor stub

            inflater = (LayoutInflater) getApplicationContext()
                    .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        }

        @Override
        public int getCount() {
            // TODO Auto-generated method stub
            return contacts.size();
        }

        @Override
        public Object getItem(int position) {
            // TODO Auto-generated method stub
            return null;
        }

        @Override
        public long getItemId(int position) {
            // TODO Auto-generated method stub
            return 0;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            // TODO Auto-generated method stub
            View vi = convertView;
            if (convertView == null) {
                vi = inflater.inflate(R.layout.layoutlist, null);
            }

            for (Contact cn : contacts) {
                String log = "Id: " + cn.getID() + " ,Name: " + cn.getName()
                        + " ,Phone: " + cn.getPhoneNumber();
                // Writing Contacts to logsout

                System.out.println("log" + log);
                TextView title2 = (TextView) vi
                        .findViewById(R.id.txt_ttlsm_row); // title
                // String song = title.get(position).toString();
                title2.setText(cn.getName());

                TextView title22 = (TextView) vi
                        .findViewById(R.id.txt_ttlcontact_row2); // notice

                title22.setText(cn.getPhoneNumber());
            }

            return vi;
        }

    }

}

Answer 1

如下所示更改MyBaseAdapter类。

public class MyBaseAdapter extends BaseAdapter {

            private LayoutInflater inflater = null;
            List<Contact> contacts;

            public MyBaseAdapter(Context applicationContext, List<Contact> contacts) {
                // TODO Auto-generated constructor stub
                this.contacts = contacts;// Initialize here
                inflater = (LayoutInflater) getApplicationContext()
                        .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            }

            @Override
            public int getCount() {
                // TODO Auto-generated method stub
                return contacts.size();
            }

            @Override
            public Object getItem(int position) {
                // TODO Auto-generated method stub
                return contacts.get(position);// Changed
            }

            @Override
            public long getItemId(int position) {
                // TODO Auto-generated method stub
                return position; //Changed
            }

            @Override
           public View getView(int position, View convertView, ViewGroup parent) {
                    // TODO Auto-generated method stub
                    View vi = convertView;
                    if (convertView == null) {
                        vi = inflater.inflate(R.layout.layoutlist, null);
                    }
                    Contact cn = (Contact) getItem(position);
                        TextView title2 = (TextView) vi
                                .findViewById(R.id.txt_ttlsm_row); // title
                        title2.setText(cn.getName());

                        TextView title22 = (TextView) vi
                                .findViewById(R.id.txt_ttlcontact_row2); // notice
                        title22.setText(cn.getPhoneNumber());
                    return vi;
                }

    }

Answer 2

你不应该在getView方法中添加for循环，而是使用这样的联系人列表：

@Override
    public View getView(int position, View convertView, ViewGroup parent) {
        // TODO Auto-generated method stub
        View vi = convertView;
        if (convertView == null) {
            vi = inflater.inflate(R.layout.layoutlist, null);
        }


            String log = "Id: " + contacts.get(position).getID() + " ,Name: " + contacts.get(position).getName()
                    + " ,Phone: " + contacts.get(position).getPhoneNumber();
            // Writing Contacts to logsout

            System.out.println("log" + log);
            TextView title2 = (TextView) vi
                    .findViewById(R.id.txt_ttlsm_row); // title
            // String song = title.get(position).toString();
            title2.setText(contacts.get(position).getName());

            TextView title22 = (TextView) vi
                    .findViewById(R.id.txt_ttlcontact_row2); // notice

            title22.setText(contacts.get(position).getPhoneNumber());


        return vi;
    }

我得到列表项同名，我在列表视图中保持for循环

2 个答案: