Question

当我遇到问题时，我正在研究我的口袋妖怪：火红色文字冒险。代码是非常基本的，但我不确定为什么它不起作用。我刚刚开始学习编程，所以我不是专家。这是代码：3

startertitle1 = "The GRASS TYPE Pokemon"
startertitle2 = "The FIRE TYPE Pokemon"
startertitle3 = "The WATER TYPE Pokemon"
x = 0
while x == 0:
    print "*** There are three POKEBALLS infront of you, which POKEBALL do you want? Pokeball     (1), (2), or (3)"
    pokeball = raw_input(">>>")
    if pokeball == "1":
        starter = "BULBASAUR"
        startertitle = startertitle1
        print "Are you sure you want to go with "+starter+", "+startertitle+"?[Y/N]"

    elif pokeball == "2":
        starter = "CHARMANDER"
        startertitle = startertitle2
        print "Are you sure you want to go with "+starter+", "+startertitle+"?[Y/N]"

    elif pokeball == "3":
        starter = "SQUIRTLE"
        startertitle = startertitle3
        print "Are you sure you want to go with "+starter+", "+startertitle+"?[Y/N]"

    sure = raw_input(">>>")
    if sure == "Y" or "y":
            print "Oak: I see! "+starter+" is your choice! This Pokemon is really quite energetic!"
            x = x+1

事先感谢您的帮助：）

问题描述：

当代码运行时，测试if sure == "Y" or "y":始终会解析为true并且始终会打印行Oak: I see!...，即使我输入N也是如此。为什么这个if()测试总是解析为真？

Answer 1

由于您没有指定目标/问题是什么，让我猜一下：

if sure == "Y" or "y":

每次评估为True，因为“y”始终为真。

提示：尝试评估以下内容：

if 'y': print 'test'

你想要的更有可能是：

if sure == "Y" or sure == "y":

Answer 2

更改

if sure == "Y" or "y"

到

if sure == "Y" or sure == "y"

更好：

if sure in ["Y", "y"]

Answer 3

你应该这样做if语句：

if sure == "Y" or sure == "y":

此外，代码缺少一小块。也就是说当一个人决定不接受他们刚刚选择的起动器时。你应该添加的是：

if sure == "N" or sure == "n":
    print starter + "not selected.\n"
    x = 0

Answer 4

在if语句

如果确定==“Y”或“y”：

它只会返回true。要解决此问题，您必须执行此操作：

如果确定==“Y”或确定==“y”：

如果您在拒绝时需要回复，那么您应该做类似的事情

如果确定==“N”或确定==“n”：打印“橡树：......”（无论你想要他说什么）

为什么这个Python if（）测试总是解析为true？

4 个答案: