Question

我似乎在CUDA中使用纹理对象时遇到了一些困难。我从here获取了代码并对其进行了简化并对其进行了充实。当我去构建它时，我得到错误“不允许输入类型名称”。它发生在我的代码的第18行，是否有人知道为什么会这样？

#include <cuda_runtime.h>
#include <texture_fetch_functions.h>
#include <cuda_texture_types.h>
#include <texture_indirect_functions.h>
#include <cuda.h>
#include "device_launch_parameters.h"
#include <vector>

#include <iostream>
#include <cstdlib>
#include <cstring>

#define L 16384

__global__ void read(cudaTextureObject_t t, float *b){
    float offset = blockIdx.x + 0.5f;
    b[blockIdx.x] = tex2D<float>(t, offset, 0.5f);
}

int main(){
    //device memory and host memory allocation
    cudaChannelFormatDesc channelFormat = cudaCreateChannelDesc(32, 0, 0, 0, cudaChannelFormatKindFloat);
    cudaArray *dev_buff_a;
    float *dev_buff_b, *hst_buff, *print_buff;
    hst_buff = (float *)malloc(L * sizeof(float));
    print_buff = (float *)malloc(L * sizeof(float));
    cudaMallocArray(&dev_buff_a, &channelFormat, L, 1);
    cudaMalloc(&dev_buff_b, L * sizeof(float));
    for(int i = 0; i < L; i++){
        hst_buff[i] = 1.0f;
    }
    //
    cudaMemcpyToArray(dev_buff_a, 0, 0, hst_buff, L * sizeof(float), cudaMemcpyHostToDevice);

    //creating the texture object
    //start with the resource descriptor
    cudaResourceDesc resource;
    memset(&resource, 0, sizeof(resource));
    resource.resType = cudaResourceTypeArray;
    resource.res.array.array = dev_buff_a;
    /*resource.res.linear.desc.f = cudaChannelFormatKindFloat;  //channel format
    resource.res.linear.desc.x = 32;    //bits per channel
    resource.res.linear.sizeInBytes = L * sizeof(float);*/

    //next, is the texture descriptor
    cudaTextureDesc texDesc;
    memset(&texDesc, 0, sizeof(texDesc));
    texDesc.readMode = cudaReadModeElementType;

    //to create the actual texture object
    cudaTextureObject_t tObj = 0;
    cudaCreateTextureObject(&tObj, &resource, &texDesc, NULL);

    //perform reading function
    dim3 block(1, 0, 0);
    dim3 grid(16384, 0, 0);
    read<<<grid, block>>>(tObj, dev_buff_b);

    //copy stuff over from dev_buff_b to print
    cudaMemcpy(print_buff, dev_buff_b, L * sizeof(float), cudaMemcpyDeviceToHost);

    //print out the arrays and compare
    std::cout << "the original array was:\n";
    for(int i = 0; i < L; i++){
        std::cout << "element " << i << "is: " << hst_buff[i] << "\n";
    }

    std::cout << "the new array is:\n";
    for(int i = 0; i < L; i++){
        std::cout << "element " << i << "is: " << print_buff[i] << "\n";
    }

    //destroy the texture object
    cudaDestroyTextureObject(tObj);
    //free device memory
    cudaFreeArray(dev_buff_a);
    cudaFree(dev_buff_b);

    return 0;
}

Answer 1

您需要确保遵循以下两点：

您正在使用Cuda 5.0或更新版
编译器设置仅针对计算能力3.0或更高版本的设备进行编译（＆nbsp;＆lt; compute_30＆＃39;标记为nvcc）

纹理对象仅适用于这些较新的设备。

CUDA纹理对象问题

1 个答案: