我有2张桌子
table 1 and table 2
user_id subtotal user_id section1_id section2_id
1 10 1 1 0
2 5 2 1 1
1 4 3 1 1
3 6 4 1 2
3 6 5 1 2
4 0 6 1 3
5 0 7 1 3
6 0 8 2 2
7 0
8 0
我做了下一个查询，根据table1.subtotal的总和对table2.user_id进行排序，其中table2_section1id = 1
SELECT table2.user_id, table2.section1_id, table2.section2_id, SUM( table1.subtotal ) AS total_price
FROM table1
LEFT JOIN table2 ON table1.user_id = table2.user_id
AND table2.section1_id =1
GROUP BY table2.user_id
ORDER BY total_price DESC
我得到了下一个结果
table2.user_id table2.section1_id table2.section2_id total_price
1 1 0 14
3 1 1 6
2 1 1 5
4 1 2 0
5 1 2 0
6 1 3 0
7 1 3 0
现在我需要根据此查询的类型更新table2.section2_id fileds作为下一个：
table2.section2_id
0 first field to be = 0
1 second field to be = table2.user_id first field value
1 third field to be = table2.user_id first field value
1 forth field to be = table2.user_id first field value
3 fifth field to be = table2.user_id second field value
3 sixth field to be = table2.user_id second field value
3 seventh field to be = table2.user_id second field value
if there are more rows lets continue
2 eighth field to be = table2.user_id third field value
2 ninth field to be = table2.user_id third field value
2 tenth field to be = table2.user_id third field value
4 eleventh field to be = table2.user_id forth field value
4 twelfth field to be = table2.user_id forth field value
4 thirteenth field to be = table2.user_id forth field value
因此直到完成所有行
请咨询