Question

我有一系列帖子，每个帖子都有一个类别。我想从这些类别的子集中显示3个帖子（我们会说a，b，c）。用核心液体有没有办法做到这一点？除非我没有想到我不认为有的东西。

帖子示例：

[
 {title: post 1, category: {id: a}},
 {title: post 2, category: {id: b}},
 {title: post 3, category: {id: c}},
 {title: post 4, category: {id: d}},
 {title: post 5, category: {id: b}}
]

我需要像这样的伪代码：

{% for post in posts where category.id == a|b|c limit: 3 %}

或

{% for post in posts %}
  {% if post.category.id == a|b|c limit: 3 %}

Answer 1

这是一种方式：

{% assign counter = 0 %}
{% for post in posts %}
  {% if counter < max and categories contains post.category.id %}
    {% assign counter = counter | plus:1 %}
    counter={{counter}}, post= {{post.title}} 
  {% endif %}
{% endfor %}

运行以下Ruby脚本：

#!/usr/bin/env ruby
require 'liquid.rb'

template = <<BLOCK
{% assign counter = 0 %}
{% for post in posts %}
  {% if counter < max and categories contains post.category.id %}
    {% assign counter = counter | plus:1 %}
    counter={{counter}}, post= {{post.title}} 
  {% endif %}
{% endfor %}
BLOCK

posts = [
  { "title" => "post 1", "category" => { "id" => "a" } },
  { "title" => "post 2", "category" => { "id" => "e" } },
  { "title" => "post 3", "category" => { "id" => "c" } },
  { "title" => "post 4", "category" => { "id" => "d" } },
  { "title" => "post 5", "category" => { "id" => "f" } },
  { "title" => "post 6", "category" => { "id" => "b" } },
  { "title" => "post 7", "category" => { "id" => "e" } },
  { "title" => "post 8", "category" => { "id" => "b" } }
]

print Liquid::Template.parse(template).render({
    'posts' => posts, 
    'max' => 3,
    'categories' => ['a', 'b', 'c']
})

产生以下输出：

counter=1, post= post 1    
counter=2, post= post 3 
counter=3, post= post 6

（虽然剥离了一些换行符）

Answer 2

您可以使用 Where Expression

{% assign posts = site.post 
| where_exp:"p", "p.category.id = 'a' or p.category.id = 'b' or p.category.id = 'c'" 
| limit: 3 %}

{% for post in posts %}
--> your code

循环条件的液体数组？

2 个答案: