Question

我这里有3个文件，index.php，authors.html.php和form.html.php，index.php是我的控制器脚本，然后调用authors.html.php来显示作者，最后是form.html。 php当用户想要编辑作者或在MySQL数据库中添加作者时。

我遇到的问题是，当用户点击更新按钮时，数据库不会更新作者详细信息...似乎我的控制器脚本没有捕获'editform'操作？我不完全确定它为什么会滑倒。以下是文件的摘录：

index.php（控制器）：

    <?php
    include $_SERVER['DOCUMENT_ROOT'] . '/includes/magicquotes.inc.php';

    if ((isset($_POST['action'])) and ($_POST['action'] == 'Edit'))
    {
        include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php'; //connect to mysql
        try
        {
            $sql = 'SELECT id, name, email FROM author WHERE id = :id';
            $s = $pdo->prepare($sql);
            $s->bindValue(':id', $_POST['id']);
            $s->execute();
        }
        catch (PDOException $e)
        {
            $error = 'Error fetching author details...';
            include 'error.html.php';
            exit();
        }

        $row = $s->fetch();

        $pageTitle = 'Edit Author';
        $action = 'editform';
        $name = $row['name'];
        $email = $row['email'];
        $id = $row['id'];
        $button = 'Update Author';

        include 'form.html.php';
        header('Location: .');
        exit();
    }

    if (isset($_GET['editform']))
    {
        include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php'; //connect to mysql

        try
        {
            $sql = 'UPDATE author SET name = :name, email = :email WHERE id = :id';
            $s->prepare($sql);
            $s->bindValue(':id', $_POST['id']);
            $s->bindValue(':name', $_POST['name']);
            $s->bindValue(':email', $_POST['email']);
            $s->execute();
        }
        catch (PDOException $e)
        {
            $error = "Error updating selected author.";
            include 'error.html.php';
            exit();
        }

        header('Location: .');
        exit();
    }

    include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';

    try
    {
        $result = $pdo->query('SELECT id, name FROM author');
    }
    catch (PDOException $e)
    {
        $error = 'Error fetching authors from the database: ';
        include 'error.html.php';
        exit();
    }

    foreach($result as $row)
    {
        $authors[] = array('id' => $row['id'], 'name' => $row['name']);
    }
    include 'authors.html.php';
    ?>

authors.html.php

    <?php include_once $_SERVER['DOCUMENT_ROOT'] . '/includes/helpers.inc.php' ?>
    // When I call "htmlout()" is the same as "echo htmlspecialchars()"
    <!DOCTYPE html>
    <html lang="en">
        <head>
            <meta charset="utf-8">
                <title>Manage Authors</title>
        </head>
        <body>
            <p>
                <h1>Manage Authors</h1>
                <p>
                    <a href="?add">Add New Author</a>
                </p>
                <ul>
                    <?php foreach ($authors as $author): ?>
                    <li>
                        <form action="?<?php $action ?>" method="post">
                            <div>
                                <?php htmlout($author['name']); ?>
                                <input type="hidden" name="id" value="<?php echo $author['id']; ?>">
                                <input type="submit" name="action" value="Edit">
                                <input type="submit" name="action" value="Delete">
                            </div>
                        </form>
                   </li>
                    <?php endforeach; ?>
                </ul>
                <p>
                    <a href="..">Return to JMS Home</a>
                </p>
            </p>
        </body>
    </html>

form.html.php

   <?php include_once $_SERVER['DOCUMENT_ROOT'] . '/includes/helpers.inc.php' ?>

   <!DOCTYPE html>
   <html lang="en">
       <head>
           <meta charset="utf-8">
               <title><?php htmlout($pageTitle); ?></title>
       </head>
       <body>
           <h1><?php htmlout($pageTitle); ?></h1>

           <form action="?<?php $action ?>" method="post">
               <div>
                   <label for="name">Name:
                       <input type="text" name="name" id="name" value="<?php htmlout($name); ?>">
                   </label>
               </div>
               <div>
                   <label for="email">Email:
                       <input type="text" name="email" id="email" value="<?php htmlout($email); ?>">
                   </label>
               </div>
               <div>
                   <input type="hidden" name="id" value="<?php htmlout($id); ?>">
                   <input type="submit" name="action" value="<?php htmlout($button) ?>">
               </div>
           </form>
       </body>
   </html>

Answer 1

我发现我做错了什么！呼...

我搞砸了这条线

$s->prepare($sql);

应该是

$s = $pdo->prepare($sql);

正如@MamaWalter指出的那样，我正在寻找$ _GET获取一个$ _POST变量，所以我改变了它现在工作得很好！

@ linus72982你使用var_dump（）的建议是一个巨大的帮助，我是PHP的新手，因此不知道它...再次感谢所有的一切！

当用户点击提交按钮时，index.php不会捕获操作并更新数据库

1 个答案: