<?php
$con = mysql_connect("localhost","root","root");
if (!$con){
die("Can not connect: " . mysql_error());
}
mysql_select_db("mydb",$con);
//Count all Total of Acc Class with same value Example Restaurant, Hotel
$query = "select acc_class,count(*) as total from mytable group by acc_class";
$result = mysql_query($query);
$values = mysql_fetch_assoc($result);
$num_total = $values['total'];
while($record = mysql_fetch_array($result)){
echo '<br>';
echo "<label>" . $record['acc_class'] . "</label>";
echo "<label>" . $num_total . "</label>";
}
mysql_close($con);
?>
伙计们请帮助我。我想生产这样的东西。但我不知道如何。
Account Class Total
------------- -----------
Hotel 5
Restaurant 2
Club 3
Church 1
我希望有一个页面,其中会显示每个帐户类的总数。请帮忙。
谢谢!
答案 0 :(得分:1)
请转储$ values:
的var_dump($值);
我猜,问题在于它是数据本身还是数据获取(数组,关联)。
请格式化SQL以提高可读性:
SELECT acc_class, COUNT(*) AS total FROM mytable GROUP BY acc_class;
Count语句是正确的:https://dev.mysql.com/doc/refman/5.7/en/counting-rows.html
解决方案:
$query = "SELECT acc_class, COUNT(*) AS total FROM mytable GROUP BY acc_class";
$result = mysql_query($query);
echo '<table border="1">';
while($row = mysql_fetch_array($result)) {
echo '<tr>';
echo '<td>' . $row['acc_class'] . '</td>';
echo '<td>' . $row['total'] . '</td>';
echo '</tr>';
}
echo '</table>';
答案 1 :(得分:1)
//you just need to put the name of the column in quert like COUNT(column_name)
$con = mysql_connect("localhost","root","root");
if (!$con){
die("Can not connect: " . mysql_error());
}
mysql_select_db("mydb",$con);
//data base connection ends here
//you write a query to fire if you want by order the put "ORDER BY HERE"
$query = "select acc_class,count(acc_class) as total from mytable group by acc_class";
//here you fire a query to mysql
$result = mysql_query($query);
//now put the selected roe in loop and again and again loop ask for more data to mysql
while($record = mysql_fetch_array($result)){
**//here you select all the group in the table**
echo '<br>';
echo "<label>" . $record['acc_class'] . "</label>";
echo "<label>" . $record['total'] . "</label>";
}
//close connection to database
mysql_close($con);