我在网上搜索了这个但无法找到解决方案,只是我想用ajax响应替换button
元素内的内容。我面临的唯一问题是,整个div正在改变而不是我点击的那个。如果我将类更改为id,则只更改第一个类而不是我想要的特定按钮。那么如何替换特定按钮的内容呢?
PHP代码:
while($row = $result->fetch_assoc()){// there are four rows so I have 4 buttons.
echo "<button class=btn btn-primary test' value='."$row['id']".'>."$row['voteup']".</button>";
}
javascript代码:
$(function() {
$('.test').on('click', function() { // attach the click to the button
var test_val = $(this).val(); // Grab the value from the button
$.ajax({
type: "GET",
url: "test.php", // Move ?tar=vrate to the data array.
data: {tar: 'vrate', test: test_val},
cache: false,
success: function(response)
{
$(".test").fadeIn('slow').html(response);//this is replacing all 4 buttons not just one, if I change the class to id, only the first one is being replaced with the response. I also tried $( .test", this) but no luck.
}
});
});
});
答案 0 :(得分:1)
$(function () {
$('.test').on('click', function () {
var test_val = $(this).val();
$.ajax({
// -------v Set the context of the callback
context: this,
type: "GET",
url: "test.php",
data: {
tar: 'vrate',
test: test_val
},
cache: false,
success: function (response) {
// v--and use `this` here
$(this).fadeIn('slow').html(response);
}
});
});
});
答案 1 :(得分:0)
尝试在此处使用$(this)
引用来实现您的目标,
$('.test').on('click', function() { // attach the click to the button
var test_val = $(this).val(); // Grab the value from the button
var $this = $(this);
$.ajax({
type: "GET",
url: "test.php", // Move ?tar=vrate to the data array.
data: {tar: 'vrate', test: test_val},
cache: false,
success: function(response)
{
$this.fadeIn('slow').html(response);
}
});
});