Question

我有这个代码应该为每个实例化抛出一个不同的异常。

Vehicle[] parkingLot = new Vehicle[5];
    try
    {
        // NEGATIVE INPUT
        parkingLot[0] = new Truck(1200.0, 2000, "Chevrolet", -8, new Person());
        // NULL MANUFACTURER
        parkingLot[1] = new Vehicle("", 8, new Person("John"));
        // NULL OWNER NAME
        parkingLot[2] = new Vehicle("Mitsubishi", 6, new Person(""));
        // TOW CAPACITY OVER 1500
        parkingLot[3] = new Truck(1700.0, 1000, "Nissan", 6, new Person("Joe"));
        // LOAD CAPACITY OVER 8600
        parkingLot[4] = new Truck(1200.0, 9000, "Nissan", 6, new Person("Frank"));
    }
    catch(Exception e)
    {
        System.out.println(e.getMessage());
    }

由于我用来创建这些对象的值是硬编码的，所以我不能使用像

这样的循环

parkingLot[index]

那么我应该如何设计我的代码，以便当一个实例化抛出异常时，仍然会尝试实例化其余的对象？

Answer 1

我认为正确的解决方案是使用单独的try ... catch块但仅仅是为了挑战，这个（java 8）代码可以做你想要的：

Callable[] initializers = {
    // NEGATIVE INPUT
    () -> parkingLot[0] = new Truck(1200.0, 2000, "Chevrolet", -8, new Person()),
    // NULL MANUFACTURER
    () -> parkingLot[1] = new Vehicle("", 8, new Person("John")),
    // NULL OWNER NAME
    () -> parkingLot[2] = new Vehicle("Mitsubishi", 6, new Person("")),
    // TOW CAPACITY OVER 1500
    () -> parkingLot[3] = new Truck(1700.0, 1000, "Nissan", 6, new Person("Joe")),
    // LOAD CAPACITY OVER 8600
    () -> parkingLot[4] = new Truck(1200.0, 9000, "Nissan", 6, new Person("Frank"))
};

for (Callable i : initializers) {
    try {
        i.call();
    } catch (Exception ex) {
        System.out.println(e.getMessage());
    }
}

单个try catch块用于数组中的多个项目

1 个答案: