如何从存档中只提取一种文件？

Question

给定一个包含10个文件的.zip或.rar存档，每个文件都有不同的扩展名。

鉴于我只想要.jpg文件。

如何在其中提取* .jpg而不必提取其他9个文件？

Answer 1

试试这个：

unzip test.zip '*.jpg'

文件名后面的参数是要提取的文件。见man unzip Arguments section：

   [file(s)]
          An  optional  list of archive members to be processed, separated
          by spaces.  (VMS versions  compiled  with  VMSCLI  defined  must
          delimit  files  with  commas instead.  See -v in OPTIONS below.)
          Regular expressions (wildcards) may be used  to  match  multiple
          members;  see  above.   Again, **be sure to quote expressions that
          would otherwise be expanded** or modified by the operating system.

Answer 2

tar -xf test.tar --wildcards --no-anchored '*.jpg'

Answer 3

您可以使用：

while read -r f; do
    tar -xf "$zipFile" "$f"
done < <(tar tf "$zipFile" | grep '\.jpg')