Question

我想实现以下，用伪mysql代码编写。

数据库表（protected_paths.tbl）：

ID  Path_Protected

1   /home/folder/private

2   /home/folder2/another-private

3   /home/folder3/subfolder/another/private-folder

4   /home/folder4/my_protected_folder

输入字符串：

Test | Match | String

1 | Y | /home/folder/private/another (caught by ID 1 above)

2 | Y | /home/folder/private/another/more (also caught by ID 1 above)

3 | N | /home/folder/work (not matched in table above)

4 | N | /home/folder/another-private (not matched in table above)

5 | N | /home/folder3/subfolder (not matched in table above - table above, ID 3, refers to deeper path)

显然不会起作用：

SELECT * FROM `protected_paths` WHERE Path_Protected = '/home/folder/private/another';

SELECT * FROM `protected_paths` WHERE Path_Protected REGEXP '/home/folder/private/another';

（我希望这与protected_paths.tbl中的ID 1匹配，因为它至少包含所有字符串）

非常感谢任何帮助。干杯，达里尔

Answer 1

如果你有很多行，它就不会很快，但这样可行。

SELECT COUNT(*)<>0 
  from tbl 
 where 'test-string' LIKE CONCAT(path_protected,'%')

见这里：http://sqlfiddle.com/#!2/d6023/3/0

Answer 2

不确定您是否需要REXEXP。您应该可以使用LIKE和CONCAT：

完成此操作

SELECT * 
FROM protected_paths 
WHERE '/home/folder/private/another' LIKE CONCAT('%',Path_Protected,'%')

SQL Fiddle Demo

Mysql REGEXP模式SELECT

2 个答案: