使用php在mysql中列出记录但只出现一条记录?

时间:2014-03-28 15:05:55

标签: php mysql wamp

<tbody>
    <?php
    $teacher_subject_query = mysql_query("select * from teacher_suject where teacher_id='$session_id'") or die(mysql_error());
    $teacher_row = mysql_fetch_array($teacher_subject_query);
    $subject_id = $teacher_row['subject_id'];

    $query = mysql_query("select * from subject where subject_id = '$subject_id'") or die(mysql_error());
    while ($row = mysql_fetch_array($query)) {
        $id = $row['subject_id'];
        ?>
           <!-- script -->
    <script type="text/javascript">
        $(document).ready(function(){

            $('#d<?php echo $subject_id; ?>').tooltip('show')
            $('#d<?php echo $subject_id; ?>').tooltip('hide')
        });
    </script>
    <!-- end script -->
    <!-- script -->
    <script type="text/javascript">
        $(document).ready(function(){

            $('#e<?php echo $subject_id; ?>').tooltip('show')
            $('#e<?php echo $subject_id; ?>').tooltip('hide')
        });
    </script>
    <!-- end script -->

        <tr class="odd gradeX">

            <td><?php echo $row['subject_code']; ?></td> 
            <td><?php echo $row['subject_title']; ?></td> 

这些是我使用的代码,但系统中只显示一条记录,我需要全部显示!提前谢谢!

2 个答案:

答案 0 :(得分:1)

必须只有一条记录符合您的查询:

$query = mysql_query("select * from subject where subject_id = '$subject_id'") or die(mysql_error());

您正在通过ID获取特定主题。

答案 1 :(得分:0)

使用

  

$ teacher_subject_query = mysql_query(“select * from teacher_suject”)或die(mysql_error());