我的表格JobOrder有5列:( jo_no，jo_type，jo_release，jo_date，jo_livedate）
使用下面的MySQL查询，我正在计算jo_type：
select jo_no, jo_date, jo_livedate, count(*) from joborder
where jo_no='1232';
输出：
+-------+-----------+-------------+----------+
| jo_no | jo_date | jo_livedate | count(*) |
+-------+-----------+-------------+----------+
| 1232 | 01-dec-14 | 05-dec-14 | 5 |
+-------+-----------+-------------+----------+
我想输出jo_date和jo_livedate的差异。如果差异是5天，我需要生成5条记录，如下所示......
+-------+-----------+-------------+
| jo_no | date | count(*)** |
+-------+-----------+-------------+
| 1232 | 01-dec-14 | 5 |
+-------+-----------+-------------+
| 1232 | 02-dec-14 | 5 |
+-------+-----------+-------------+
| 1232 | 03-dec-14 | 5 |
+-------+-----------+-------------+
| 1232 | 04-dec-14 | 5 |
+-------+-----------+-------------+
| 1232 | 05-dec-14 | 5 |
+-------+-----------+-------------+