当我们在任何开放式解决方案中打开Package Manager Console时,它会显示该解决方案的所有项目。如何加载同一解决方案的所有项目。 当我尝试使用下面显示的代码时,它正在获取我打开的第一个解决方案的项目。
private List<Project> GetProjects()
{
var dte = (DTE)Marshal.GetActiveObject(string.Format(CultureInfo.InvariantCulture, "VisualStudio.DTE.{0}.0", targetVsVersion));
var projects = dte.Solution.OfType<Project>().ToList();
return projects;
}
答案 0 :(得分:22)
以下是一组允许您枚举给定解决方案中的项目的函数。这就是您在当前解决方案中使用它的方法:
// get current solution
IVsSolution solution = (IVsSolution)Microsoft.VisualStudio.Shell.Package.GetGlobalService(typeof(IVsSolution));
foreach(Project project in GetProjects(solution))
{
....
}
....
public static IEnumerable<EnvDTE.Project> GetProjects(IVsSolution solution)
{
foreach (IVsHierarchy hier in GetProjectsInSolution(solution))
{
EnvDTE.Project project = GetDTEProject(hier);
if (project != null)
yield return project;
}
}
public static IEnumerable<IVsHierarchy> GetProjectsInSolution(IVsSolution solution)
{
return GetProjectsInSolution(solution, __VSENUMPROJFLAGS.EPF_LOADEDINSOLUTION);
}
public static IEnumerable<IVsHierarchy> GetProjectsInSolution(IVsSolution solution, __VSENUMPROJFLAGS flags)
{
if (solution == null)
yield break;
IEnumHierarchies enumHierarchies;
Guid guid = Guid.Empty;
solution.GetProjectEnum((uint)flags, ref guid, out enumHierarchies);
if (enumHierarchies == null)
yield break;
IVsHierarchy[] hierarchy = new IVsHierarchy[1];
uint fetched;
while (enumHierarchies.Next(1, hierarchy, out fetched) == VSConstants.S_OK && fetched == 1)
{
if (hierarchy.Length > 0 && hierarchy[0] != null)
yield return hierarchy[0];
}
}
public static EnvDTE.Project GetDTEProject(IVsHierarchy hierarchy)
{
if (hierarchy == null)
throw new ArgumentNullException("hierarchy");
object obj;
hierarchy.GetProperty(VSConstants.VSITEMID_ROOT, (int)__VSHPROPID.VSHPROPID_ExtObject, out obj);
return obj as EnvDTE.Project;
}
答案 1 :(得分:3)
可能有一个更好的方法,但我快速了解并发现这个工作(它假设您有一种方式知道解决方案名称)。根据{{3}},GetActiveObject
不保证VS的当前实例,这就是您从另一个实例获取结果的原因。相反,您可以使用此处显示的GetDTE
方法:
[DllImport("ole32.dll")]
private static extern int CreateBindCtx(uint reserved, out IBindCtx ppbc);
public static DTE GetDTE(int processId)
{
string progId = "!VisualStudio.DTE.10.0:" + processId.ToString();
object runningObject = null;
IBindCtx bindCtx = null;
IRunningObjectTable rot = null;
IEnumMoniker enumMonikers = null;
try
{
Marshal.ThrowExceptionForHR(CreateBindCtx(reserved: 0, ppbc: out bindCtx));
bindCtx.GetRunningObjectTable(out rot);
rot.EnumRunning(out enumMonikers);
IMoniker[] moniker = new IMoniker[1];
IntPtr numberFetched = IntPtr.Zero;
while (enumMonikers.Next(1, moniker, numberFetched) == 0)
{
IMoniker runningObjectMoniker = moniker[0];
string name = null;
try
{
if (runningObjectMoniker != null)
{
runningObjectMoniker.GetDisplayName(bindCtx, null, out name);
}
}
catch (UnauthorizedAccessException)
{
// Do nothing, there is something in the ROT that we do not have access to.
}
if (!string.IsNullOrEmpty(name) && string.Equals(name, progId, StringComparison.Ordinal))
{
Marshal.ThrowExceptionForHR(rot.GetObject(runningObjectMoniker, out runningObject));
break;
}
}
}
finally
{
if (enumMonikers != null)
{
Marshal.ReleaseComObject(enumMonikers);
}
if (rot != null)
{
Marshal.ReleaseComObject(rot);
}
if (bindCtx != null)
{
Marshal.ReleaseComObject(bindCtx);
}
}
return (DTE)runningObject;
}
如果您事先知道解决方案名称,则可以在MainWindowTitle
的{{1}}属性中找到它,并将Process
传递给上述方法。
ProcessID
虽然上面的代码有效,但我遇到了一个COM错误,我使用var dte = GetDTE(System.Diagnostics.Process.GetProcesses().Where(x => x.MainWindowTitle.StartsWith("SolutionName") && x.ProcessName.Contains("devenv")).FirstOrDefault().Id);
类this post修复了该错误。
从那篇文章中,这就是MessageFilter
类的样子
MessageFilter
然后你可以像这样访问项目名称
public class MessageFilter : IOleMessageFilter
{
// Class containing the IOleMessageFilter
// thread error-handling functions.
// Start the filter.
public static void Register()
{
IOleMessageFilter newFilter = new MessageFilter();
IOleMessageFilter oldFilter = null;
CoRegisterMessageFilter(newFilter, out oldFilter);
}
// Done with the filter, close it.
public static void Revoke()
{
IOleMessageFilter oldFilter = null;
CoRegisterMessageFilter(null, out oldFilter);
}
//
// IOleMessageFilter functions.
// Handle incoming thread requests.
int IOleMessageFilter.HandleInComingCall(int dwCallType,
System.IntPtr hTaskCaller, int dwTickCount, System.IntPtr lpInterfaceInfo)
{
//Return the flag SERVERCALL_ISHANDLED.
return 0;
}
// Thread call was rejected, so try again.
int IOleMessageFilter.RetryRejectedCall(System.IntPtr
hTaskCallee, int dwTickCount, int dwRejectType)
{
if (dwRejectType == 2)
// flag = SERVERCALL_RETRYLATER.
{
// Retry the thread call immediately if return >=0 &
// <100.
return 99;
}
// Too busy; cancel call.
return -1;
}
int IOleMessageFilter.MessagePending(System.IntPtr hTaskCallee,
int dwTickCount, int dwPendingType)
{
//Return the flag PENDINGMSG_WAITDEFPROCESS.
return 2;
}
// Implement the IOleMessageFilter interface.
[DllImport("Ole32.dll")]
private static extern int
CoRegisterMessageFilter(IOleMessageFilter newFilter, out
IOleMessageFilter oldFilter);
}
[ComImport(), Guid("00000016-0000-0000-C000-000000000046"),
InterfaceTypeAttribute(ComInterfaceType.InterfaceIsIUnknown)]
interface IOleMessageFilter
{
[PreserveSig]
int HandleInComingCall(
int dwCallType,
IntPtr hTaskCaller,
int dwTickCount,
IntPtr lpInterfaceInfo);
[PreserveSig]
int RetryRejectedCall(
IntPtr hTaskCallee,
int dwTickCount,
int dwRejectType);
[PreserveSig]
int MessagePending(
IntPtr hTaskCallee,
int dwTickCount,
int dwPendingType);
}
答案 2 :(得分:2)
我相信你可以使用这样的东西:
var dte = (EnvDTE.DTE)GetService(typeof(EnvDTE.DTE));
if (dte != null)
{
var solution = dte.Solution;
if (solution != null)
{
// get your projects here
}
}