Question

我有一种情况，当我试图从父对象制作一个json字符串时，gson也会返回子对象元素。如何消除相同。

这是我的代码。

Class Image {
    private int imageID;
    private String imageName;

    // Getters and setters
}

Class ImageDetails extends Image {
    private String imageType;
    private byte[] imageData;
    //Getters and setters
}


Class Test {
    // Setting the image Object, and the imageDetails.

    // calling the gson for json string
    String jsonString = GsonString.UserFeed(ImageObject)

    // This jsonString has all the elements from the ImageDetails Object also which i do not want.
}

Class GsonString {

    public static String UserFeed(Object feedData) {
        String feeds = null;
        Gson gson = new Gson();
        feeds = gson.toJson(feedData);
        return feeds;
    }
}

Answer 1

您只需使用toJson(Object src,Type typeOfSrc)

指定要序列化的班级

一个简单的例子：

class Bob {
    private String bobName = "Bob";
}

class Pete extends Bob {
    private String peteName = "Bob";
}

public static void main(String[] args) {

    Object o = new Pete();
    System.out.println(new Gson().toJson(o));
    System.out.println(new Gson().toJson(o, Bob.class));

}

<强>输出：

{"peteName":"Bob","bobName":"Bob"}
{"bobName":"Bob"}

Gson到json也返回子类的所有元素

1 个答案: