这是我的Count_query：
Declare @yes_count decimal;
Declare @no_count decimal;
set @yes_count=(Select count(*) from Master_Data where Received_Data='Yes');
set @no_count=(Select count(*) from Master_Data where Received_Data='No');
select @yes_count As Yes_Count,@no_count as No_Count,(@yes_count/(@yes_count+@no_count)) As Submission_Count
我无法在这两个查询上加入
这是查询的其余部分：
Select Distinct D.Member_Id,d.Name,d.Region_Name, D.Domain,e.Goal_Abbreviation,
e.Received_Data, case when Received_Data = 'Service Not Provided' then null
when Received_Data = 'No' then null else e.Improvement end as
Percent_Improvement , case when Received_Data = 'Service Not Provided' then null
when Received_Data = 'No' then null else e.Met_40_20 end as Met_40_20
FROM (
select distinct member_Domains.*,
(case when NoData.Member_Id is null then 'Participating' else ' ' end) as Participating
from
(
select distinct members.Member_Id, members.Name, Members.Region_Name,
case when Domains.Goal_Abbreviation = 'EED Reduction' then 'EED'
When Domains.Goal_Abbreviation = 'Pressure Ulcers' then 'PRU'
when Domains.Goal_Abbreviation = 'Readmissions' then 'READ' else Domains.Goal_Abbreviation end as Domain from
(select g.* from Program_Structure as ps inner join Goal as g on ps.Goal_Id = g.Goal_Id
and ps.Parent_Goal_ID = 0) as Domains
cross join
(select distinct hc.Member_ID, hc.Name,hc.Region_Name from zsheet as z
inner join Hospital_Customers$ as hc on z.CCN = hc.Mcare_Id) as Members
) as member_Domains
left outer join Z_Values_Hospitals as NoData on member_Domains.member_ID = NoData.Member_Id
and Member_Domains.Domain = noData.ReportName) D
Left Outer JOIN
(SELECT B.Member_ID, B.Goal_Abbreviation, B.minRate, C.maxRate, B.BLine, C.Curr_Quarter, B.S_Domain,
(CASE WHEN B.Member_ID IN
(SELECT member_id
FROM Null_Report
WHERE ReportName = B.S_Domain) THEN 'Service Not Provided' WHEN Curr_Quarter = 240 THEN 'Yes' ELSE 'No' END) AS Received_Data,
ROUND((CASE WHEN minRate = 0 AND maxRate = 0 THEN 0 WHEN minRate = 0 AND maxRate > 0 THEN 1 ELSE (((maxRate - minRate) / minRate) * 100) END), .2) AS Improvement,
(CASE WHEN ((CASE WHEN minRate = 0 AND maxRate = 0 THEN 0 WHEN minRate = 0 AND maxRate > 0 THEN 1 ELSE (maxRate - minRate) / minRate END)) <= - 0.4 OR
maxRate = 0 THEN 'Yes' WHEN ((CASE WHEN minRate = 0 AND maxRate = 0 THEN 0 WHEN minRate = 0 AND maxRate > 0 THEN 1 ELSE (maxRate - minRate) / minRate END))
<= - 0.2 OR maxRate = 0 THEN 'Yes' ELSE 'No' END) AS Met_40_20
FROM (SELECT tab.Member_ID, tab.Measure_Value AS minRate, tab.Goal_Abbreviation, A.BLine, tab.S_Domain
FROM Measure_Table_Description AS tab INNER JOIN
(SELECT DISTINCT
Member_ID AS new_memid, Goal_Abbreviation AS new_measure, MIN(Reporting_Period_ID) AS BLine, MAX(Reporting_Period_ID)
AS Curr_Quarter
FROM Measure_Table_Description
WHERE (Member_ID > 1) AND (Measure_Value IS NOT NULL) AND (Measure_ID LIKE '%O%')
GROUP BY Goal_Abbreviation, Member_ID) AS A ON tab.Member_ID = A.new_memid AND tab.Reporting_Period_ID = A.BLine AND
tab.Goal_Abbreviation = A.new_measure) AS B FULL OUTER JOIN
(SELECT tab.Member_ID, tab.Measure_Value AS maxRate, tab.Goal_Abbreviation, A_1.Curr_Quarter
FROM Measure_Table_Description AS tab INNER JOIN
(SELECT DISTINCT
Member_ID AS new_memid, Goal_Abbreviation AS new_measure,
MIN(Reporting_Period_ID) AS BLine, MAX(Reporting_Period_ID)
AS Curr_Quarter
FROM Measure_Table_Description AS Measure_Table_Description_1
WHERE (Member_ID >1) AND (Measure_Value IS NOT NULL) AND (Measure_ID LIKE '%O%')
GROUP BY Goal_Abbreviation, Member_ID) AS A_1 ON tab.Member_ID = A_1.new_memid
AND tab.Reporting_Period_ID = A_1.Curr_Quarter AND
tab.Goal_Abbreviation = A_1.new_measure) AS C ON B.Member_ID = C.Member_ID
WHERE (B.Goal_Abbreviation = C.Goal_Abbreviation) ) E ON D.Member_Id = E.Member_ID AND d.Domain = E.S_Domain
ORDER BY D.Domain,D.Member_ID
如何将每个member_ID的＆＃39; yes＆＃39; /（count（yes）+ count（no））计数为column1，并显示每个member_ID对所有member_ID的排名结果为column2。我已经提出了一个生成整个表的计数的查询，但是如何限制每个Member_ID。
感谢您的帮助。
答案 0 :(得分：0)
我还没有花时间来消化你提供的查询，但如果抽象出在每一行上重复一系列数据的概念，你应该看一下使用窗口函数。还有其他方法，例如使用CTE进行聚合，然后再加入到详细数据中。对于更复杂的计算，这可能会更好，但窗口函数可以说是更优雅的选项。
DECLARE @MasterData AS TABLE
(
MemberID varchar(50),
MemberAnswer int
);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jim', 1);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jim', 0);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jim', 1);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jim', 1);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jane', 1);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jane', 0);
INSERT INTO @MasterData (MemberID, MemberAnswer) VALUES ('Jane', 1);
-- Method 1, using windowing functions (preferred for performance and syntactical compactness)
SELECT
MemberID,
MemberAnswer,
CONVERT(numeric(19,4),SUM(MemberAnswer) OVER (PARTITION BY MemberID)) / CONVERT(numeric(19,4),COUNT(MemberAnswer) OVER (PARTITION BY MemberID)) AS PercentYes
FROM @MasterData;
-- Method 2, using a CTE
WITH MemberSummary AS
(
SELECT
MemberID,
SUM(MemberAnswer) AS MemberYes,
COUNT(MemberAnswer) AS MemberTotal
FROM @MasterData
GROUP BY MemberID
)
SELECT
md.MemberID,
md.MemberAnswer,
CONVERT(numeric(19,4),MemberYes) / CONVERT(numeric(19,4),MemberTotal) AS PercentYes
FROM @MasterData md
JOIN MemberSummary ms
ON md.MemberID = ms.MemberID;
答案 1 :(得分：0)
首先想到的是：你的查询太复杂了。我花了大约10分钟时间试图理解它并且没有任何进展，所以它显然会给你组织内部的人带来长期的维护挑战。我真的建议你尝试找一些简化它的方法。
也就是说，这是一个简化的一般示例，说明如何查询计算值并对结果进行排名：
CREATE TABLE member (member_id INT PRIMARY KEY);
CREATE TABLE master_data (
transaction_id INT PRIMARY KEY,
member_id INT FOREIGN KEY REFERENCES member(member_id),
received_data BIT
);
-- INSERT data here
; WITH member_data_counts AS (
SELECT
m.member_id,
(SELECT COUNT(*) FROM master_data d WHERE d.member_id = m.member_id AND d.received_data = 1) num_yes,
(SELECT COUNT(*) FROM master_data d WHERE d.member_id = m.member_id AND d.received_data = 0) num_no
FROM member m
), member_data_calc AS (
SELECT
*,
CASE
WHEN (num_yes + num_no) = 0 THEN NULL -- avoid division-by-zero error
ELSE num_yes / (num_yes + num_no)
END pct_yes
FROM member_data_counts
), member_data_rank AS (
SELECT *, RANK() OVER (ORDER BY pct_yes DESC) AS RankValue
FROM member_data_calc
)
SELECT *
FROM member_data_rank
ORDER BY RankValue ASC;