Question

Android - 如何检查另一个以逗号分隔的字符串中是否存在字符串值。

 String all_vals  = "617,618,456,1,234,5,5678,225";
 String check_val= "456";

如何检查，

 if (all_vals contains check_val) { 

 }

Answer 1

将逗号分隔的字符串转换为包含split的数组，然后将其转换为List Arrays.asList，然后使用contains。

String all_vals = "617,618,456,1,234,5,5678,225";
List<String> list = Arrays.asList(all_vals.split(","));
if (list.contains(check_val)) {

}

这样可以防止误报只是检查字符串中是否存在contains直接在字符串all_vals上的子字符串，例如all_vals.contains("4")会在直接true案例中返回String#contains。

Answer 2

    String all_vals  = "617,618,456,1,234,5,5678,225";
    String check_val= "5678";
    int place = 1;

    String[] strings = all_vals.split(",");
    for (String str : strings) {
        if(str.equals(check_val))
        {
            System.out.println("We have string in all_val on place: " + place);
        }
        place++;
    }

Answer 3

$(".class").on('change', function(){
    var id = $(this).attr("id");
    $("#"+id).closest("tr").toggleClass("checked", this.checked);
});

Answer 4

Java 8：

String all_vals  = "617,618,456,1,234,5,5678,225";
String check_val= "5678";
Arrays.stream(all_vals.split(",")).anyMatch(check_val:: equals)
if(Arrays.stream(all_vals.split(",")).anyMatch(check_val:: equals)){
    System.out.println("The value is present");
 }

Answer 5

Ref :: https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#contains(java.lang.CharSequence)

public boolean contains(CharSequence s)

仅当此字符串包含指定的char值序列时才返回true。

Ex

/******************************************************************************
                 public boolean contains(CharSequence s)
*******************************************************************************/


public class Main
{
    public static void main(String[] args) {
        String all_vals  = "617,618,456,1,234,5,5678,225";
        String check_val= "456";
        System.out.println("String contains :: "+all_vals.contains(check_val));
    }
}

Android - 如何检查另一个逗号分隔字符串中是否存在字符串值

5 个答案: