如何有条件地删除元组列表中的元素？

Question

>>> x=[("x1","x2","x3"),("x1","x2"),("x2","x3"),("x3","x4")]
>>> x
[('x1', 'x2', 'x3'), ('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]

我想要删除列表中的元组 - x，如果len(x[id])==3，len(x[0]==3)，那么它将被删除，[('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]是我想要的，我怎么能写出来码？

[del element if len(element[id]==3) for id,element in enumerate(x)]

invalid syntax.

Answer 1

使用列表推导来过滤元素，保留所有不是长度为3的内容：

x = [el for el in x if len(el) != 3]

演示：

>>> x = [('x1', 'x2', 'x3'), ('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]
>>> [el for el in x if len(el) != 3]
[('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]