Question

您好我使用tkinter创建了一个GUI，它接受来自用户的输入。我创建了自己的状态检查和拼写＆＃39;检查以确保用户仅输入接受的值。但每次输入这些值时，用户都会在输出屏幕出现之前多次单击提交按钮。这是因为我使用了多种功能吗？还有其他方法吗？

def Search():
    global E1, E2, E3, E4, file

    def PresenceValidation():

        if E1.get() ==(''):
            root2=Tk()
            errortext = Label(root2, text = "Please enter eye colour")  
            errortext.pack()
        elif E2.get() ==(''):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter age")
            errortext.pack()
        elif E3.get() ==(''):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter hair colour")
            errortext.pack()
        elif E4.get() ==(''):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter shoesize")
            errortext.pack()            
        else:
            button = Button(root, text = "Submit information", command=SpellCheck)
            button.grid(row=3, column=2, padx = 5)

    def SpellCheck():
        if E1.get().lower() not in ('blue', 'brown', 'green'):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter eye colour")
            message= Label(root2, text = "Blue, Brown or Green")
            errortext.pack()
            message.pack()
        elif E2.get().lower()  not in ('10-20', '20-30', '30-40','40+'):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter a valid age group")
            message=Label(root2, text = "10-20, 20-30, 30-40 or 40+")
            errortext.pack()
            message.pack()
        elif E3.get().lower()  not in ('Brown', 'Black', 'Blonde', 'Auburn'):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter a valid hair colour")
            message = Label(root2, text = "Brown, Black, Blonde or Auburn")
            errortext.pack()
            message.pack()
        elif E4.get().lower() not in ('1', '2', '3','4','5','6','7','8+'):
            root2=Tk()
            root2.configure(bg="white")
            errortext = Label(root2, text = "Please enter a valid shoesize")
            message = Label(root2, text = "1,2,3,4,5,6,7,8+")
            errortext.pack()
            message.pack()         
        else:
            submitbutton = Button(window, text = "Submit information", command=Submit)
            submitbutton.grid(row=3, column=2, padx = 5)   


    root = Tk()
    root.title ("Search for matches")



    #text that will be shown to the user
    root.configure(bg="white")
    Label(root, text="Please enter eye colour").grid(row=0)
    Label(root, text="Please enter age").grid(row=1)
    Label(root, text="Please enter hair colour").grid(row=2)
    Label(root, text="Please enter shoesize").grid(row=3)


    #Create user entry points
    E1= Entry(root)
    E2= Entry(root)
    E3= Entry(root)
    E4= Entry(root)
    # locating input boxes to area on the screen
    E1.grid(row=0, column=1)
    E2.grid(row=1, column=1)
    E3.grid(row=2, column=1)
    E4.grid(row=3, column=1)




    submitbutton = Button(window, text = "Submit information", command=PresenceValidation)
    submitbutton.grid(row=3, column=2, padx = 5)

    def Quit():
    window.destroy()

    quitbton = Button (window, text ="QUIT", command=Quit)
    quitbton.grid(row=3, column=3, padx=5)

Answer 1

您可以重写此代码以省略大量代码，并使其按照您希望的方式运行。你得到多个按钮的原因是因为你正在制作多个按钮。其中三个，如果我把它们全部计算在内。初始Submit按钮应调用一个函数来验证字段，如果它运行的值不正确，则会跳出循环。您还可以使用Messagebox来提示用户错误的位置。

如果您不添加Messagebox并希望保持原样，则应将root2实例更改为Toplevel小部件，以避免创建两个Tkinter实例。这也可能导致意想不到的结果。

以下是您可以轻松查看状态的示例：

from tkMessageBox import showwarning

def PresenceValidation():
    #Make dictionary to hold values
    values = {'Eye color': E1.get(),
              'Age': E2.get(),
              'Hair': E3.get(),
              'Shoesize': E4.get()
              }

    #Iterate over dictionary to check for empty items
    for k,v in values.iteritems():
        if v == '':
            showwarning('Empty Value Alert',    #Create alert message
                        k + ' needs a value')   #for the first empty value,
            break                               #and break out of the loop

Answer 2

您的部分问题是您正在创建多个根窗口。 Tkinter不是为那种方式工作而设计的。如果您需要更多窗口，请创建Toplevel。

的实例

为什么我必须多次点击按钮？ tkinter gui

2 个答案: