我从awstats文件生成这个数组$months
,如下所示:
Array
(
[0] => Array
(
[0] => 10
[1] => 37
[2] => 11
)
[1] => Array
(
[0] => 11
[1] => 34
[2] => 19
)
[2] => Array
(
[0] => 12
[1] => 20
[2] => 11
)
)
哪个$months[0][0]
代表一个月的数量以及$months[0][1]
个数据。我想要做的是使用它的数据构建一个具有一年中所有月份的数组,如果它没有一个数组到0
。
像这样:
Array
(
[0] => Array
(
[0] => 01
[1] => 41
[2] => 52
)
[1] => Array
(
[0] => 02
[1] => 74
[2] => 66
)
[2] => Array
(
[0] => 03
[1] => 40
[2] => 83
)
[3] => Array
(
[0] => 04
[1] => 0
[2] => 0
)
[4] => Array
(
[0] => 05
[1] => 0
[2] => 0
)
[5] => Array
(
[0] => 06
[1] => 0
[2] => 0
)
依此类推......有什么办法可以实现这个目标吗?非常感谢!
答案 0 :(得分:0)
这是我的想法(如果我理解你的问题):
首先,创建另一个包含12个元素的数组($ sortedMonths),然后用空数据填充它们:
$sortedMonths = array();
for ($i = 1; $i <= 12; $i++) {
$sortedMonths[] = array($i, 0, 0);
}
/*
Array
(
[0] => Array
(
[0] => 1,
[1] => 0,
[2] => 0
)
...
[11] => Array
(
[0] => 12,
[1] => 0,
[2] => 0
)
)
*/
然后循环$ months并将数据分配给$ sortedMonths的相应元素:
foreach ($months as $month) {
$sortedMonths[$month[0]-1] = $month;
}