Question

我正在使用JBoss 6.0.2进行eclipse。我将一些EJB作为Web服务公开，并且成功。

但是在我想揭露的最后一个Ejb上，当我在JBoss上部署我的应用程序时，我收到了这个错误：

Caused by: com.sun.xml.bind.v2.runtime.IllegalAnnotationsException: 2 counts of IllegalAnnotationExceptions
com.upsilon.beans.pfselection.SelectionCriterium is an interface, and JAXB can't handle interfaces.
        this problem is related to the following location:
                at com.upsilon.beans.pfselection.SelectionCriterium
                at private java.util.ArrayList com.upsilon.beans.pfselection.SelectionCriteria.criteria
                at com.upsilon.beans.pfselection.SelectionCriteria
                at private java.util.ArrayList com.upsilon.beans.client.jaxws_asm.GetPortfolios.arg2
                at com.upsilon.beans.client.jaxws_asm.GetPortfolios
com.upsilon.beans.pfselection.SelectionCriterium does not have a no-arg default constructor.
        this problem is related to the following location:
                at com.upsilon.beans.pfselection.SelectionCriterium
                at private java.util.ArrayList com.upsilon.beans.pfselection.SelectionCriteria.criteria
                at com.upsilon.beans.pfselection.SelectionCriteria
                at private java.util.ArrayList com.upsilon.beans.client.jaxws_asm.GetPortfolios.arg2
                at com.upsilon.beans.client.jaxws_asm.GetPortfolios

        at com.sun.xml.bind.v2.runtime.IllegalAnnotationsException$Builder.check(IllegalAnnotationsException.java:106
        at com.sun.xml.bind.v2.runtime.JAXBContextImpl.getTypeInfoSet(JAXBContextImpl.java:466)
        at com.sun.xml.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:298)
        at com.sun.xml.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:141)
        at com.sun.xml.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1157)
        at com.sun.xml.bind.v2.ContextFactory.createContext(ContextFactory.java:145)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) [rt.jar:1.7.0_51]

这是我的界面：

public interface SelectionCriterium //extends Serializable
{

}

这是我的SelectionCriteria类

public class SelectionCriteria //implements Serializable
{


    private ArrayList<SelectionCriterium> criteria = new ArrayList<SelectionCriterium>( );

public SelectionCriteria(){}

public SelectionCriteria( ArrayList<SelectionCriterium> criteria )
{
    this.criteria = criteria;
}

/*public SelectionCriteria( )
{
    criteria = new ArrayList<SelectionCriterium>( );
}*/


public ArrayList<SelectionCriterium> getCriteria( )
{
    return criteria;
}

public void setCriteria( ArrayList<SelectionCriterium> criteria )
{
    this.criteria = criteria;
}

public void addCriterium( SelectionCriterium criterium )
    {
        criteria.add( criterium );
    }
}

我尝试使用Xml注释，但它不起作用：/

如果有人有想法？非常感谢（对不起我的英语）

Answer 1

如果您有一个作为接口类型的映射字段/属性，则需要使用@XmlElement注释来指定实现类型。

@XmlElement(type=SelectionCriteriumImpl.class)
public ArrayList<SelectionCriterium> getCriteria( )
{
    return criteria;
}

其他信息

您可以在我的博客上找到有关此用例的更多信息：

http://blog.bdoughan.com/2011/05/jaxb-and-interface-fronted-models.html

JAXB不想使用接口

1 个答案: