Question

我使用包含所有类别名称，获奖者和被提名者的文本文件创建了一个包含奥斯卡信息的对象数组（获奖者也出现在被提名者列表中）。我现在想要能够询问用户。您想知道哪个类别的获胜者？一旦提出问题，它就会回答问题。我只能让它在数组的最后一个对象上工作（最佳视觉效果返回重力）。有人可以解释为什么会这样吗？

class AwardCategory 
  attr_accessor :winner, :name, :nominees
  def initialize(name)
    @name = name
    @nominees = []
  end
end 

class Nominee
  attr_accessor :name
  def initialize(name)
    @name = name 
  end
end 

file = File.open('oscar_noms.txt', 'r')

oscars = []
begin
  while true do
    award_category = AwardCategory.new(file.readline.downcase)
    award_category.winner = file.readline.downcase

    nominee = Nominee.new(file.readline.downcase)
    award_category.nominees << nominee

    next_nominee = Nominee.new(file.readline.downcase)
    until next_nominee.name == "\n"
      award_category.nominees << next_nominee
      next_nominee = Nominee.new(file.readline.downcase)
    end
    oscars << award_category
  end
rescue EOFError => e
  puts 'rescued'
end

#puts oscars.inspect

#Read input here
puts "What category do you want to know the winner for?"
  answer = gets
  oscars.each 
  if answer.downcase == award_category.name
    puts award_category.winner
  else
    puts "That is not a category"
    end

Answer 1

那段代码

puts "What category do you want to know the winner for?"
  answer = gets
  oscars.each 
  if answer.downcase == award_category.name
    puts award_category.winner
  else
    puts "That is not a category"
    end

现在有正确的缩进

puts "What category do you want to know the winner for?"
answer = gets
oscars.each 
if answer.downcase == award_category.name
  puts award_category.winner
else
  puts "That is not a category"
end

请注意，oscars.each下面的部分没有缩进，因为each需要一个do / end块，它将为每个元素执行一次。你可能想要的是这个

puts "What category do you want to know the winner for?"
answer = gets
oscars.each do |award_category|
  if answer.downcase == award_category.name
    puts award_category.winner
  else
    puts "That is not a category"
  end
end

虽然我建议您不要使用其他内容，因为对于每个不匹配的答案，您都会收到"That is not a category"消息。此外，您应该使用gets.chomp从用户输入中删除换行符，并在downcase循环之外执行each。最后一点，你的一些变量命名不佳。例如，为什么奖项类别列表应该命名为oscars？它应该是award_categories。

根据Ruby中对象数组的用户输入输出正确的对象属性

1 个答案: