我有以下功能替换了一个可信的textarea中的链接。它有效,但在100个字符左右变慢。如何才能更快地优化此功能?
function makeLinksFrom (str) {
var wordArray = str.replace(/(<([^>]+)>)/ig,"").split(' ');
var domainsArray = ['.com', '.net', '.co', '.ca', '.io', '.me'];
wordArray.forEach(function(word) {
domainsArray.forEach(function(domain) {
if(word.indexOf(domain) != -1 && word.substr(word.length - 6) == ' ') {
if(word.indexOf('http://') == -1) {
str = str.replace(word, '<a target="_blank" contenteditable="false" href="http://'+clean(word)+'">link</a> ');
} else {
str = str.replace(word, '<a target="_blank" contenteditable="false" href="'+clean(word)+'">link</a> ');
}
}
});
});
return str;
}
答案 0 :(得分:1)
您不必重复检查每个单词。您需要做的就是将字符串中的单词放在哈希中,然后为每个案例创建一次超链接字。然后只替换已更改的单词。我就是这样做的。希望这会有所帮助。
function makeLinksFrom (str) {
var wordArray = str.replace(/(<([^>]+)>)/ig,"").split(' ');
var domainsArray = ['.com', '.net', '.co', '.ca', '.io', '.me'];
var positions = {};
wordArray.forEach(function(word){
var value = positions[word];
positions[word] = 1;
});
var keys = Object.keys(positions);
var cleanWord = {};
keys.forEach(function(key){
domainsArray.forEach(function(domain){
if(key.indexOf(domain) != -1 && key.substr(word.length - 6) == ' ') {
if(key.indexOf('http://') == -1){
cleanWord[key] = '<a target="_blank" contenteditable="false" href="http://'+clean(word)+'">link</a> ';
}else{
cleanWord[key] = '<a target="_blank" contenteditable="false" href="'+clean(word)+'">link</a> ';
}
}
});
});
keys.forEach(function(key){
if(key != cleanWord[key])
str = str.replace(key, cleanWord[key]);
});
return str;
}
如果您不介意丢失多余的空格,您可能需要将代码的下半部分替换为以下内容
keys.forEach(function(key){
domainsArray.forEach(function(domain){
if(key.indexOf(domain) != -1 && key.substr(word.length - 6) == ' ') {
if(key.indexOf('http://') == -1){
cleanWord[key] = '<a target="_blank" contenteditable="false" href="http://'+clean(word)+'">link</a> ';
}else{
cleanWord[key] = '<a target="_blank" contenteditable="false" href="'+clean(word)+'">link</a> ';
}
}else{
cleanWord[key] = word;
}
});
});
var newArr = [];
wordArray.forEach(function(word){
newArr.push(cleanWord[word]);
});
return newArr.join(" ");
答案 1 :(得分:0)
您可以替换此行
domainsArray.forEach(function(domain) {
if(word.indexOf(domain) != -1 && word.substr(word.length - 6) == ' ')
使用正则表达式验证,如:
if (work.match(/.+\\.(com|net|co|ca|io|me)/) != null && word.substr(word.length - 6) == ' ')
你会有更快的速度和相同的结果!
答案 2 :(得分:0)
您需要使用单词哈希将算法拆分为两个单独的循环(不是另一个循环)。它看起来像(没有经过测试,但你有一个想法):
var hash = {};
var key;
var i;
for (i=0; i<wordArray.length; i++) {
for (var j=0; j<domainsArray.length; j++);
key = word[i] + "/" + domain[j];
hash[key] = key;
}
}
for (key in hash) {
word = hash[key].split('/')[0];
domain = hash[key].split('/')[1];
if (word.indexOf(domain) != -1 ...
....
....
}