Question

我编写了简单的REST Web服务客户端类，它使用JAX-RS 2.0客户端API来发出REST请求。我试图弄清楚如何为每次调用设置请求超时。以下是请求的代码：

Client client = ClientBuilder.newBuilder().build();
WebTarget resourceTarget = client.target(restServiceUrl)
        .path("{regsysID}/{appointmentID}/")
        .resolveTemplate("regsysID", regSysId)
        .resolveTemplate("appointmentID", apptId);

Invocation invocation = resourceTarget.request(MediaType.APPLICATION_JSON).buildPut(null);
String createSessionJson = invocation.invoke(String.class);

Answer 1

注意：这是JAX-RS 2.1

上提供的新方法

这是一个非常古老的帖子，但以下代码适用于球衣和重新设计。

ClientBuilder clientBuilder = ClientBuilder.newBuilder();
clientBuilder.connectTimeout(10, TimeUnit.SECONDS);
clientBuilder.readTimeout(12, TimeUnit.SECONDS);
Client client = clientBuilder.build();

Answer 2

您可以先创建ClientConfig并在创建新客户端时将其作为参数提供。

import org.glassfish.jersey.client.ClientProperties;

ClientConfig configuration = new ClientConfig();
configuration.property(ClientProperties.CONNECT_TIMEOUT, 1000);
configuration.property(ClientProperties.READ_TIMEOUT, 1000);
Client client = ClientBuilder.newClient(configuration);

Answer 3

使用Resteasy可以通过构建您的客户端来实现。

Client client = new ResteasyClientBuilder()
    .establishConnectionTimeout(2, TimeUnit.SECONDS)
    .socketTimeout(2, TimeUnit.SECONDS)
    .build();

我还没有看到您可以通过ClientBuilder.newClient(Configuration configuration)设置的标准配置属性列表，这些属性是实现此便携式所需的。

Answer 4

首先，您必须添加相关的依赖项（这里是WildFly 10.1）：

<dependency>
    <groupId>org.apache.httpcomponents</groupId>
    <artifactId>httpclient</artifactId>
    <version>4.5</version>
    <scope>provided</scope>
</dependency>
<dependency>
    <groupId>org.jboss.resteasy</groupId>
    <artifactId>resteasy-client</artifactId>
    <version>3.0.14.Final</version>
    <scope>provided</scope>
</dependency>

接下来 - 创建一个普通的Apache HttpClient并将其推送到RestEasy Enginge并重写一个方法，这会导致问题：

// create here a normal Apache HttpClient with all parameters, that you need
HttpClient httpClient = createHttpClient(connectTimeout,
                                         socketTimeout,
                                         connectionRequestTimeout,
                                         maxTotalHTTPConnections);
// Deprecated Apache classes cleanup https://issues.jboss.org/browse/RESTEASY-1357
// Client Framework not honoring connection timeouts Apache Client 4.3 https://issues.jboss.org/browse/RESTEASY-975
ApacheHttpClient4Engine engine = new ApacheHttpClient4Engine(httpClient) {
        @Override
        protected void loadHttpMethod(ClientInvocation request, HttpRequestBase httpMethod) throws Exception {
            super.loadHttpMethod(request, httpMethod);
            httpMethod.setParams(new BasicHttpParams());
        }
    };

return new ResteasyClientBuilder().httpEngine(engine).build();

看看https://issues.jboss.org/browse/RESTEASY-975似乎，问题刚刚在版本3.1.0.Final中得到解决。

Answer 5

对于那些使用较旧的JAX-RS 2.0 API和较旧的Resteasy实现的人，可以使用以下方法：

Client client = new ResteasyClientBuilder()             
     .establishConnectionTimeout(3, TimeUnit.SECONDS)
     .socketTimeout(5, TimeUnit.SECONDS).build();

尽管有名称，socketTimeout代表“读取超时”，因为在文档中，它代表“等待数据的超时”。

Answer 6

如果您使用的是Jersey 2.x，这是对我有用的简单解决方案

import com.jclient.JClient;

Client c = Client.create();
WebResource webResource = c.resource("requestUrl");
c.setConnectTimeout(yourMins*60*1000);

设置JAX-RS 2.0 Client API的请求超时

6 个答案: