Question

所以我的 routes.php 中有一个变量，我想将它传递给route :: get，这是我的代码以获取更多详细信息：

$user = User::find(Auth::user()->username);
Route::get('/services/here i want to put my variable', 'ServiceController@show');

所以，如果有人知道我会非常感激

Answer 1

使用以下内容来改变路线的问题：

$user = User::find(Auth::user()->username);
Route::get("/services/$user->username", 'ServiceController@show');

在用户不存在的情况下，您是否可能会遇到一些问题。如果您这样做并转到命令行并执行：

php artisan routes

将不会记录用户，以便将路线指向/services/。您需要做的就是创建一个过滤器并在其上处理您的路线：

路线：

Route::get("/services/{username}", array('before' => 'user-must-be-logged-in', 'uses' => 'ServiceController@show'));

对其进行一些检查的过滤器：

Route::filter('user-must-be-logged-in', function()
{
    if ( ! Auth::check())
    {
        App::abort(404); /// user is not logged in, this route does not exist
    }

    if ( ! User::where('username', $username)->first() )
    {
        App::abort(404); /// user does not exists, this route does not exist
    }

    if (User::where('username', $username)->first()->id !== Auth::user()->id)
    {
        App::abort(404); /// selected is not the current logged user, this route does not exist
    }
});

控制器用它做任何你需要的事情：

class ServiceController extends Controller {

    public function show()
    {
        $user = User::where('username', $username)->first();

        // now do whatever you need with your user;
    }

}

Answer 2

假设你想要放在那里的$ user

$user = User::find(Auth::user()->username);
Route::get("/services/$user", 'ServiceController@show');

交换单引号用于双打并传入你的var（或者用你的单引号删除连接。你的var

如何将变量传递给laravel中的路由？

2 个答案: