Question

说我想查找两个日期之间的所有星期一，date_A和date_B

from datetime import date, timedelta
days_to_substract = 50
date_A = date.today()-timedelta(days=days_to_subtract)
date_B = date.today()

我该怎么做？有没有办法在日期之间进行迭代？

Answer 1

您可以使用生成器迭代日期范围：

def date_range(date1,date2):
    while date1 < date2:
        yield date1
        date1 = date1 + timedelta(days=1)

并像这样迭代：

for dat in date_range(date_A,date_B):
    <your code here>

Answer 2

你的意思是这样吗？

def day_iter(start, end):
    step = timedelta(days=1)
    for i in range((end - start).days):
        yield start + i*step

end = date.today()
start = end - timedelta(days=50)
for day in day_iter(start, end):
    day.weekday() == 0:
        print day.strftime("%A  %Y-%m-%d")

输出：

Monday  2014-02-10
Monday  2014-02-17
Monday  2014-02-24
Monday  2014-03-03
Monday  2014-03-10
Monday  2014-03-17
Monday  2014-03-24

您也可以这样做：

today = date.today()
past = today - timedelta(50)
if past.weekday() != 0:
    monday = past + timedelta(7 - past.weekday())
else:
    monday = past
one_week = timedelta(7)
while monday < today:
    print monday
    monday += one_week

输出：

你可以将它概括为这样的函数：

def past_weekdays(depth, weekday):
    today = date.today()
    past = today - timedelta(depth)
    if past.weekday() != weekday:
        past_day = past + timedelta((7 + (weekday - past.weekday())) % 7)
    else:
        past_day = past
    one_week = timedelta(7)
    while past_day < today:
        yield past_day
        past_day += one_week

Answer 3

从当前日期查找上周一，并根据7天差异查找剩余时间：

from datetime import date, timedelta
days_to_substract = 50
date_A = date.today()-timedelta(days=days_to_substract)
date_B = date.today()
cDay = date_B - timedelta(days=date_B.weekday())
print cDay
while cDay > date_A:
    cDay = cDay - timedelta(days=7)
    print cDay

输出：

Answer 4

也许这个：

from datetime import date, timedelta

days_to_substract = 50
date_A = date.today()-timedelta(days=days_to_substract)
date_B = date.today()

date_tmp = date_A

numOfMondays = 0
deltaStep = 1

while date_tmp < date_B:
    if date_tmp.strftime("%A") != "Monday":
        print("Date before first monday {}".format(date_tmp))
        date_tmp += timedelta(days=1)
    else:
        print("Monday : {}".format(date_tmp))
        date_tmp += timedelta(days=7)
        numOfMondays += 1

print("from {} to {} there are {} monday".format(date_A, date_B, numOfMondays))

带输出

Date before first monday 2014-02-05
Date before first monday 2014-02-06
Date before first monday 2014-02-07
Date before first monday 2014-02-08
Date before first monday 2014-02-09
Monday : 2014-02-10
Monday : 2014-02-17
Monday : 2014-02-24
Monday : 2014-03-03
Monday : 2014-03-10
Monday : 2014-03-17
Monday : 2014-03-24
from 2014-02-04 to 2014-03-26 there are 7 monday

查找两个日期之间的日期

4 个答案: