Question

我正在寻找一种获取通用结果集的方法，并使用jQuery Dyantree将其转换为使用ASP.NET MVC的树结构。我有一个测试类，如：

public class GenericResults
{
    public string ClaimId { get; set; }
    public string DrugName { get; set; }
    public int PatientId { get; set; }

    //simulates database call, this could be any type of result set
    public static List<GenericResults> MockDatabaseCall()
    {
        return new List<GenericResults>()
        {
            new GenericResults { ClaimId = "abc", DrugName="Drug 1",  PatientId=1 },
            new GenericResults { ClaimId = "bcd", DrugName="Drug 2",  PatientId=1 },
            new GenericResults { ClaimId = "def", DrugName="Drug 3",  PatientId=1 },
            new GenericResults { ClaimId = "fgi", DrugName="Drug 4",  PatientId=1 },
            new GenericResults { ClaimId = "ijk", DrugName="Drug 5",  PatientId=2 },
            new GenericResults { ClaimId = "klm", DrugName="Drug 6",  PatientId=2 },
            new GenericResults { ClaimId = "mno", DrugName="Drug 7",  PatientId=2 },
            new GenericResults { ClaimId = "pqr", DrugName="Drug 8",  PatientId=2 },
            new GenericResults { ClaimId = "qrs", DrugName="Drug 9",  PatientId=2 },
            new GenericResults { ClaimId = "stu", DrugName="Drug 10", PatientId=2 },
        };
    }
}

Dynatree数据所需的结构如下：

public string Title { get; set; }
public List<TreeView> Children { get; set; }
public bool IsFolder
{
    get
    {
        return this.Children.Count > 0;
    }
}

在这个例子中，我们真的不需要ClaimId属性，但是我想重用我已经编写的存储过程来提供给树，所以我想要包含它。我需要将已分组的内容转换为自己的TreeView对象，并将Children属性作为所有具有分组值的记录。到目前为止MockDatabaseCallMethod，如果我在PatientId分组，我需要两个TreeView个对象：每个唯一的PatientId一个。我希望能够递归地执行此操作，但不确定如何因为某些项目将是叶子（没有孩子）而且这很好。这是我的尝试：

public class TreeView
{
    public string Title
    {
        get;
        set;
    }

    public List<TreeView> Children { get; set; }

    public bool IsFolder
    {
        get
        {
            return this.Children.Count > 0;
        }
    }

    //made void for the time being to limit compilation errors
    public static void ListToTree(string displayName,string groupedOn)
    {
        //seed data
        List<GenericResults> results = GenericResults.MockDatabaseCall();

        //"group" on the property passed by the user
        var query = results.Select(x => x.GetType().GetProperty(groupedOn).GetValue(x,null)).Distinct();

        foreach (var i in query)
        {
            var treeView = new TreeView();
            treeView.Title = displayName;

            //iterate over results, if object has the property value of what's currently being iterated over
            //create a new TreeView object for it
            treeView.Children = results.Where(x => x.GetType().GetProperty(groupedOn).GetValue(x, null) == i)
                                       .Select(n => new TreeView
                                                    {
                                                        Title = displayName,
                                                        Children = x <--no idea what to do here
                                                    });
        }
    }
}

理想情况下，我希望使用ToTree扩展方法，但首先我想对此进行一些指导。谢谢:)

Answer 1

我不确定我是否理解正确，但如果我这样做，我会建议以下解决方案：

- ）在TreeView中，将属性public List<TreeView> Children { get; set; }更改为public IEnumerable<GenericResults> Children { get; set; }。

- ）用以下方法替换void ListToTree(string displayName方法：

public static List<TreeView> ListToTree(string displayName, string groupedOn)
{
    //seed data
    List<GenericResults> results = GenericResults.MockDatabaseCall();

    List<TreeView> trees = new List<TreeView>();

    //"group" on the property passed by the user
    var query = results.Select(x => x.GetType().GetProperty(groupedOn).GetValue(x, null)).Distinct();

    foreach (int i in query)
    {
        var treeView = new TreeView();
        treeView.Title = displayName;
        treeView.Children = results.Where(x => ((int)x.GetType().GetProperty(groupedOn).GetValue(x, null)) == i);

        trees.Add(treeView);
    }

    return trees;
}

我不确定，如果我理解正确的话; - ）

使用递归属性ASP.NET / C＃

1 个答案: