Question

我有这张表：

路径：

idTokenN idPath   token      isTV
   1      p1      test1      true
   2      p1      test2      false
   3      p2      test3      true
   4      p3      test4      false
   5      p3      test5      false
   6      p4      test6      false
   7      p4      test7      true
   8      p4      test8      false
   9      p4      test9      false
   10     p5      test10     true
   11     p5      test11     false
   12     p5      test12     false

关系：

    idTokenN  idTokenN2   rel
       10      11         test

我想获得包含至少一个值Istv“true”和idPath的idPath，包括通过某个阈值，即通过设置最小值和最大值。例如，如果强加为最小值：2且最多3个idPath长，我将只得到2到3之间：

    idPath  token   isTV    rel
      p1    test1   true    null
      p1    test2   false   null
      p5    test10  true    test
      p5    test11  false   null
      p5    test12  false   null

我试过这个查询，部分工作，我不知道如何设置idPath的范围：

SELECT path.idPath, path.token, path.isTV,relation.rel 
FROM path 
    LEFT OUTER JOIN relation ON(path.idTokenN=relation.idTokenN)
WHERE path.idPath IN (
        SELECT path.idPath FROM path WHERE path.isTV='true');

Answer 1

为什么不这一个？

SELECT path.idPath, path.token, path.isTV,relation.rel
FROM path
LEFT OUTER JOIN relation ON (path.idTokenN=relation.idTokenN)
WHERE path.idPath IN(SELECT DISTINCT path.idPath FROM path WHERE path.isTV='true')
AND path.idPath IN(SELECT DISTINCT path.idPath FROM path GROUP BY path.idPath HAVING COUNT(*) >= 2 AND COUNT(*) <= 3)

Answer 2

SELECT 
    path.idPath, 
    path.token, 
    path.isTV,relation.rel 
FROM path 
LEFT OUTER JOIN relation 
    ON(path.idTokenN=relation.idTokenN)
GROUP BY idPath
HAVING SUM(isTV='true')>0
    AND COUNT(DISTINCT path.idTokenN) BETWEEN  2 AND 3

SQL查询：从某个阈值中获取值

2 个答案: