<?php
$connection = mysql_connect('###', '###', '###');
mysql_select_db('msg360db1');
$sql = "SELECT * FROM call_log where Pod = 'KNF'";
$result = mysql_query($sql);
echo
"<table cellspacing='0' cellpadding='0'>
";
while($row = mysql_fetch_array($result))
{
echo "
<tr>
<td style='margin-right:10px;'>" . $row['Rep'] . "</td>
<td style='margin-right:10px;'>" . $row['EWD'] . "</td>
<td style='margin-right:10px;'>" . $row['CalltimeThisWeek'] . "</td>
<td style='margin-right:10px;'></td>
<td style='margin-right:10px;'>" . $row['CallsThisWeek'] . "</td>
<td style='margin-right:10px;'></td>
<td style='margin-right:10px;'>" . $row['CalltimeToday'] . "</td>
<td style='margin-right:10px;'>" . $row['CallsToday'] . "</td>
</tr>
";
}
echo "
</table>";
mysql_close();
?>
<?php
$row['CalltimeThisWeek'];
$row['EWD'];
$number = ($row['EWD'] / $row['CalltimeThisWeek']);
echo 'Result: '.$number;
?>
我已连接到我的数据库并成功创建了一个包含其中信息的表,但是,我想要将本周的调用时间除以EWD,该值是1到7之间的值,这些值存储在我的数据库中
答案 0 :(得分:0)
你正试图在范围之外使用$ row数组。解释一下,你需要对每一行进行除法,还是先将它们全部加起来进行除法?
答案 1 :(得分:0)
试试这个:
if($row['CalltimeThisWeek']==0){
$number = 0;
} else {
$number = ($row['EWD'] / $row['CalltimeThisWeek']);
}
循环后这些不是必需的:
$row['CalltimeThisWeek'];
$row['EWD'];
此外,您需要将时间戳转换为可分整数: http://php.net/manual/en/function.mktime.php
别忘了: 然后,您需要将$ number数学和echo语句放在while循环中,否则它将仅使用它在变量中获得的最后一个数字并生成一个结果。
答案 2 :(得分:0)
你不能除以零;这就是你得到的错误,
替换此
<?php
$row['CalltimeThisWeek'];
$row['EWD'];
$number = ($row['EWD'] / $row['CalltimeThisWeek']);
echo 'Result: '.$number;
?>
由此:
<?php
$number=0;
if($row['CalltimeThisWeek']!=0) $number = $row['EWD'] / $row['CalltimeThisWeek']);
echo 'Result: '.$number;
?>
答案 3 :(得分:0)
您需要检查$ row ['EWD']和$ row ['CalltimeThisWeek']是否为0或负值
if ($row['EWD'] >= 1 && $row['CalltimeThisWeek'] >= 1) {
$number = ($row['EWD'] / $row['CalltimeThisWeek']);
} else {
$number = 0;
}