Question

假设我有一个班级，例如：

class User{
     function callname(){
         $user = $_SESSION['id'];
         $query = ("SELECT * FROM user WHERE user.id='$user'");
         while ($result=mysql_fetch_array($query)){
              echo ($result['username']);}}}

然后，为User对象创建实例：

$user = new User;

发送邮件的代码：

if($_SERVER["REQUEST_METHOD"] == "POST"){
$username = trim($_POST['username']);
$check = mysql_num_rows(mysql_query("SELECT * FROM user WHERE username='$username'"));

if ($check==TRUE){
    $name = $user->callname();
    $to = "myemail@domain.com";
    $subject = "Example Subject";
    $headers = "From: My Domain".'\r\n'.
      "MIME-Version: 1.0".'\r\n'.
      "Content-Type: text/html; charset=ISO-8859-1".'\r\n'.
      'X-Mailer: PHP/' . phpversion();
    $message = "Hai $name, this is the new message.";

            mail($to, $subject, $message, $headers);
} else {
    ?>
        <script type="text/javascript">
            alert("Sorry, username not exist !");
        </script>
        <?php
}

}

邮件功能正常，我也收到了一封电子邮件。问题是

$name没有在电子邮件中打印用户名。我已经在$name = $user->callname();的不同页面上尝试了这个if()而且它正在运行。
\r\nMIME-Version: 1.0依旧在From标题中打印。

Answer 1

我认为你需要return $result['username']而不是回应它。
对于特殊字符，您需要使用双引号（＆＃34;）。

尝试更正您的代码：

class User{
     function callname(){
         $user = $_SESSION['id'];
         $query = mysql_query("SELECT * FROM user WHERE user.id='$user'");
         while ($result=mysql_fetch_array($query)){
              return $result['username'];}}}

下一部分：

if($_SERVER["REQUEST_METHOD"] == "POST"){
$username = mysql_real_escape_string(trim($_POST['username']));
$check = mysql_num_rows(mysql_query("SELECT * FROM user WHERE username='$username'"));

if ($check==TRUE){
    $name = $user->callname();
    $to = "myemail@domain.com";
    $subject = "Example Subject";
    $headers = "From: My Domain"."\r\n".
      "MIME-Version: 1.0"."\r\n".
      "Content-Type: text/html; charset=ISO-8859-1"."\r\n".
      'X-Mailer: PHP/' . phpversion();
    $message = "Hai $name, this is the new message.";

            mail($to, $subject, $message, $headers);
} else {
    ?>
        <script type="text/javascript">
            alert("Sorry, username not exist !");
        </script>
        <?php
}

为什么mime在标题中打印而无法调用变量？

1 个答案: