下面是我的PHP代码的一部分,它以数组格式回显结果。我试图这样做,所以它将结果发布在一个表中。我该怎么办?
//-display the result of the array
echo "<ul>\n";
echo "<li>" . "<a href=\"search_search.php?id=$ID\">" .
$FirstName . " " . $LastName . " " . $Email . "</a></li>\n";
echo "</ul>";
答案 0 :(得分:0)
执行html table-
之类的操作echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['Email'] . "</td>";
echo "</tr>";
}
echo "</table>";
答案 1 :(得分:-1)
返回基础,http://www.w3schools.com/php/php_mysql_select.asp
查看在HTML表格中显示结果。