Question

使用表单更新对象后，对于其中一个字段（foo）中的某个值，我想检查是否存在具有特定属性值的持久子对象。

所以我创建了一个自定义验证器，将doctrine作为参数传递，但是..如何传递对象（或对象的id）和foo的特定值来创建查询？

这是我的代码：

class ChildCategoryHasItsOwnPageValidator extends ConstraintValidator
{
    protected $doctrine;

    public function __construct(RegistryInterface $doctrine)
    {
        $this->doctrine = $doctrine;
    }


    public function validate($value, Constraint $constraint)
    {
      //...
    }
}

Placas\FrontendBundle\Entity\Category:
    properties:
        ownPage:
            - Placas\FrontendBundle\Validator\Constraints\ChildCategoryHasItsOwnPage: ~

/**
 * @Annotation
 */
class ChildCategoryHasItsOwnPage extends Constraint
{
    public $message = 'This category has a child category with an own page. You can not define an own page for this category.';

    public function validatedBy()
    {
      return "child_category_has_its_own_page";
    }
}

Placas\FrontendBundle\Entity\Category:
    properties:
        ownPage:
            - Placas\FrontendBundle\Validator\Constraints\ChildCategoryHasItsOwnPage: ~

Answer 1

我想这会对你有所帮助：http://symfony.com/doc/current/reference/constraints/Callback.html

它应该像你这样工作：（Symfony 2.4版）

您的配置：

Placas\FrontendBundle\Entity\Category:
    constraints:
        - Callback: [validate]

在你的实体中：

use Symfony\Component\Validator\ExecutionContextInterface;

class Category
{
    public function validate(ExecutionContextInterface $context)
    {
        $children = $this->getChildren(); // assuming you have this relationship and its getter
        foreach ($children as $child)
        {
            if ($child->foo != '') // or whatever test you want to make
            {
                $context->addViolationAt(
                   'foo',
                   'This category has a child category with an own page. You can not define an own page for this category.',
                   array(),
                   null
                );
            }
        }
    }
}

symfony2：验证取决于查询

1 个答案: