Question

我有这样的XML

<reg>
  <user>
       <Name> abc</Name>
       <Email> abc@xyz.com</Email>
       <picture> sdCard/imges.145.jpg </Picture>
       <Date> 12/12/2012</Date>
  </user>
  <user>
       <Name> abc dfg</Name>
       <Email> ertdg@xyz.com</Email>
       <picture> sdCard/imges.145.jpg </Picture>
       <Date> 23/12/2013</Date>
  </user>
</reg>

我想获取特定节点的值并将它们添加到ArrayList以在ListView中显示我试过这段代码，但它只给出了Last Record

的值

Users setUser = new Users();
final ArrayList<Users> uData = new ArrayList<Users>();
Document xmlDocument = builder.parse(file);

                XPath xPath =  XPathFactory.newInstance().newXPath();


                String expression = "/reg/user/Name";
                System.out.println(expression);

                NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODESET);
                for (int i = 0; i < nodeList.getLength(); i++) {
                    System.out.println(nodeList.item(i).getTextContent());
                   setUser.setName(nodeList.item(i).getTextContent());

               }
                String expression1 = "/reg/user/Email";
                System.out.println(expression1);

              NodeList nodeList1 = (NodeList) xPath.compile(expression1).evaluate(xmlDocument, XPathConstants.NODESET);
                for (int i = 0; i < nodeList1.getLength(); i++) {
                    System.out.println(nodeList1.item(i).getTextContent());
                   setUser.setEmail(nodeList1.item(i).getTextContent());
               }
                String expression2 = "/reg/user/Picture";
                System.out.println(expression2);

                NodeList nodeList2 = (NodeList) xPath.compile(expression2).evaluate(xmlDocument, XPathConstants.NODESET);
                for (int i = 0; i < nodeList2.getLength(); i++) {
                    System.out.println(nodeList2.item(i).getTextContent());
                   setUser.setimage(nodeList2.item(i).getTextContent());
               }
                String expression3 = "/reg/user/LastEdited";
                System.out.println(expression3);

                NodeList nodeList3 = (NodeList) xPath.compile(expression3).evaluate(xmlDocument, XPathConstants.NODESET);
                for (int i = 0; i < nodeList3.getLength(); i++) {
                    System.out.println(nodeList3.item(i).getTextContent());
                   setUser.setDate(nodeList3.item(i).getTextContent()); 


                }  uData.add(setUser);

如何让它显示所有记录？

Answer 1

您的代码仅为评论中的@playmaker420解释了Last Record的值。要解决此问题，您可以尝试循环遍历<user>元素，而不是分别遍历每个<name>，<email>，<picture>和<date>：

XPath xPath =  XPathFactory.newInstance().newXPath();
String expression = "/reg/user";

NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
    Users setUser = new Users();
    Element el = (Element) nodeList.item(i);

    String name = el.getElementsByTagName("Name").item(0).getTextContent();
    setUser.setName(name);

    String email = el.getElementsByTagName("Email").item(0).getTextContent();
    setUser.setEmail(email);

    String picture = el.getElementsByTagName("picture").item(0).getTextContent();
    setUser.setimage(picture);

    String date = el.getElementsByTagName("Date").item(0).getTextContent();
    setUser.setDate(date);

    uData.add(setUser);
}

从XML获取特定节点值并添加到ArrayLIst

1 个答案: