我试图在不使用任何asp控件的情况下上传图片。到目前为止,我一直在尝试:
<form id="form1" data-ajax="false" method="post" runat="server" enctype="multipart/form-data">
<input type="file" id="uploadFile" name="uploadFile" runat="server"/>
<input type="submit" class="btn-login" data-corners="true" value="Yükle" onclick="UploadPhoto()" />
</form>
在我的.aspx页面和JQuery中的UploadPhoto()方法中:
function UploadPhoto() {
$.ajax({
type: "POST",
url: "IncidentChange.aspx/UploadPhoto",
contentType: "application/json; charset=utf-8",
success: function (msg) {
},
error: function () {
}
});
}
我发布了C#代码。但是,我无法从codebehind到达上传的项目。
[WebMethod]
public static string UploadPhoto()
{
try
{
byte[] fileData = null;
using (var binaryReader = new BinaryReader(HttpContext.Current.Request.Files[0].InputStream))
{
fileData = binaryReader.ReadBytes(HttpContext.Current.Request.Files[0].ContentLength);
}
}
catch (Exception ex)
{
}
return null;
}
但是Request.Files似乎是一个空数组。由于该方法是静态的([WebMethod]),我无法在方法中到达输入控件来获取发布的文件。我怎样才能克服这个问题?谢谢。
答案 0 :(得分:2)
HTML:
<input type="file" id="uploadFile" name="uploadFile"/>
<input type="button" id="submit" value="Submit" onClick="UploadFile();"/>
的JQuery:
<script type="text/javascript">
$(document).ready(function () {
function UploadFile() {
var fileName = $('#uploadFile').val().replace(/.*(\/|\\)/, '');
if (fileName != "") {
$.ajaxFileUpload({ url: 'AjaxFileUploader.ashx',
secureuri: false,
fileElementId: 'uploadFile',
dataType: 'json',
success: function (data, status) {
if (typeof (data.error) != 'undefined') {
if (data.error != '') {
alert(data.error);
} else {
alert('Success');
}
}
},
error: function (data, status, e) {
alert(e);
}
}
)
}
}
});
请从tyhe bekow链接下载ajax文件上传器插件。
http://www.phpletter.com/DOWNLOAD/
处理程序:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.IO;
using System.Text.RegularExpressions;
using System.Text;
namespace MyProject
{
public class AjaxFileUploader : IHttpHandler
{
{
public void ProcessRequest(HttpContext context)
{
if (context.Request.Files.Count > 0)
{
string path = context.Server.MapPath("~/UploadImages");
if (!Directory.Exists(path))
Directory.CreateDirectory(path);
var file = context.Request.Files[0];
string fileName;
if (HttpContext.Current.Request.Browser.Browser.ToUpper() == "IE")
{
string[] files = file.FileName.Split(new char[] { '\\' });
fileName = files[files.Length - 1];
}
else
{
fileName = file.FileName;
}
string newFilename = Guid.NewGuid().ToString();
FileInfo fInfo = new FileInfo(fileName);
newFilename = string.Format("{0}{1}", newFilename, fInfo.Extension);
string strFileName = newFilename;
fileName = Path.Combine(path, newFilename);
file.SaveAs(fileName);
string msg = "{";
msg += string.Format("error:'{0}',\n", string.Empty);
msg += string.Format("msg:'{0}'\n", strFileName);
msg += "}";
context.Response.Write(msg);
}
}
public bool IsReusable
{
get
{
return true;
}
}
}
}
答案 1 :(得分:1)
是的,你可以通过ajax post方法实现这个目标。在服务器端,您可以使用httphandler。
使用ajax,您也可以显示上传进度。
您必须将文件作为输入流读取。
using (FileStream fs = File.Create("D:\\_Workarea\\" + fileName))
{
Byte[] buffer = new Byte[32 * 1024];
int read = context.Request.GetBufferlessInputStream().Read(buffer, 0, buffer.Length);
while (read > 0)
{
fs.Write(buffer, 0, read);
read = context.Request.GetBufferlessInputStream().Read(buffer, 0, buffer.Length);
}
}
示例代码
function sendFile(file) {
debugger;
$.ajax({
url: 'handler/FileUploader.ashx?FileName=' + file.name, //server script to process data
type: 'POST',
xhr: function () {
myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) {
myXhr.upload.addEventListener('progress', progressHandlingFunction, false);
}
return myXhr;
},
success: function (result) {
//On success if you want to perform some tasks.
},
data: file,
cache: false,
contentType: false,
processData: false
});
function progressHandlingFunction(e) {
if (e.lengthComputable) {
var s = parseInt((e.loaded / e.total) * 100);
$("#progress" + currFile).text(s + "%");
$("#progbarWidth" + currFile).width(s + "%");
if (s == 100) {
triggerNextFileUpload();
}
}
}
}
答案 2 :(得分:0)
为什么你没有使用默认的asp控件?最好使用.Net框架工作提供的默认控件。使用默认控件将删除任何长期运行的依赖项。