我正在尝试从字符串中获取浮点数或整数。 因为这是我的测试用例..
1) str="IN100RINR" Output = 100;
2) str="IN100RINR" Output = 100;
3) str="100INR" Output = 100;
4) str="100.50INR" Output = 100.50;
5) str="IN100.50R" Output = 100.50;
6) str="INR100.50" Output = 100.50;
7) str="INR100INRINR20.500INR" Output = 100
这一切都在我的程序中工作,但案例7不起作用..返回100.500
这是我的代码......
Pattern pattern = Pattern.compile("(\\d+)");
String str="INR100INRINR20.500INR", amount="", decimal="";
if(str.contains(".")){
String temp= str.substring(str.indexOf(".")+1);
Matcher matcher = pattern.matcher(temp);
if(matcher.find()){
decimal = matcher.group();
}
}
Matcher matcher = pattern.matcher(str);
if(matcher.find()){
if(decimal != ""){
amount=matcher.group()+"."+decimal;
}else{
amount = matcher.group();
}
System.out.println(Float.valueOf(amount));
}
答案 0 :(得分:11)
您可以使用简单的匹配器/查找方法来执行类似的操作:
Pattern pattern = Pattern.compile("\\d+(?:\\.\\d+)?"); // Match int or float
String str="INR100INRINR20.500INR";
Matcher matcher = pattern.matcher(str);
if(matcher.find()){
System.out.println(matcher.group());
}