Question

我是SQL 2012的新手，需要你的帮助。我已经设法将以下查询放在一起并且它有效，当我尝试按照第3个表中的类别类型进行分组时失败。不确定如何加入，但是遇到绑定错误。

所以基本上，2 where（select from）语句可以工作，但我不能得到c.category。（表名：ELM_HO.dbo.BCX_ExclusionsJan2013）

请您提供指导。谢谢

SELECT c.category
    ,count (c.category)
      ,count(distinct b.[ACCOUNT NUMBER])
    ,sum([30 DAYS BAL]) as [30 DAYS]
      ,sum([30 DAYS VAT BAL]) as [30 DAYS VAT]
      ,sum([60 DAYS BAL]) as [60 DAYS]
      ,sum([60 DAYS VAT BAL])as [60 DAYS VAT]
      ,sum([90 DAYS BAL]) as [90 DAYS]
      ,sum([90 DAYS VAT BAL]) as [90 DAYS VAT]
      ,sum([REST]) as [REST]
      ,sum([VAT REST]) as [REST VAT]
    ,sum(b.[30 DAYS BAL]) + sum(b.[30 DAYS VAT BAL])+ sum(b.[60 DAYS BAL]) + sum(b.[60 DAYS VAT BAL]) + sum(b.[90 DAYS BAL]) + sum(b.[90 DAYS VAT BAL]) +sum(b.[REST]) + sum(b.[VAT REST]) as [TOTAL PAYMENTS]
  FROM [ELM_BP348].[dbo].[BP348JUL2013] as b]
  where b.[ACCOUNT NUMBER] in (SELECT [Account Number] FROM [TIMS].[dbo].[TIMS90-Claim_JUL2013])
  and b.[ACCOUNT NUMBER] in (select [Account no] from ELM_HO.dbo.BCX_ExclusionsJan2013 as c)
  group by c.category

Answer 1

由于您没有提供任何数据，我无法对此进行测试，但我认为这可能是您想要的：

SELECT 
    c.category,
    COUNT(c.category),
    COUNT(DISTINCT b.[ACCOUNT NUMBER]),
    SUM([30 DAYS BAL]) as [30 DAYS],
    SUM([30 DAYS VAT BAL]) as [30 DAYS VAT],
    SUM([60 DAYS BAL]) as [60 DAYS],
    SUM([60 DAYS VAT BAL])as [60 DAYS VAT],
    SUM([90 DAYS BAL]) as [90 DAYS],
    SUM([90 DAYS VAT BAL]) as [90 DAYS VAT],
    SUM([REST]) as [REST],
    SUM([VAT REST]) as [REST VAT],
    SUM(b.[30 DAYS BAL]) + SUM(b.[30 DAYS VAT BAL])+ SUM(b.[60 DAYS BAL]) + SUM(b.[60 DAYS VAT BAL]) + SUM(b.[90 DAYS BAL]) + SUM(b.[90 DAYS VAT BAL]) +SUM(b.[REST]) + SUM(b.[VAT REST]) as [TOTAL PAYMENTS]
  FROM [ELM_BP348].[dbo].[BP348JUL2013] AS b
  INNER JOIN ELM_HO.dbo.BCX_ExclusionsJan2013 AS c ON b.[ACCOUNT NUMBER] = c.[Account no]  
  WHERE b.[ACCOUNT NUMBER] in (SELECT [Account Number] FROM [TIMS].[dbo].[TIMS90-Claim_JUL2013])
  GROUP BY c.category

您也可以将WHERE子句替换为另一个内连接。

2从“第3表”中选择“来自语句，组”

1 个答案: