正确的SQL语句来获取员工的迟到和OT

Question

以下是我的SQL查询：

select Employee_Number, Cast([DateTime] as Date) as 'DateTime', MIN([DateTime]) as 'MIN', MAX([DateTime]) as 'MAX' , [Hours Worked] =
CAST((DATEDIFF(HOUR ,min([DateTime]), max([DateTime])) / 24) AS VARCHAR) +
' Days ' +
CAST((DATEDIFF(HOUR , min([DateTime]),  max([DateTime])) % 24) AS VARCHAR) +
' Hours ' +
CAST((DATEDIFF(MINUTE, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
' Minutes ' +
CAST((DATEDIFF(SECOND, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
' Seconds '  , [Over Time] = CAST((DATEDIFF(HOUR, '17:30:00:000', MAX([DateTime])) % 24) AS VARCHAR) + ' Hours ' + 
CAST((DATEDIFF(MINUTE, '17:30:00:000', max([DateTime])) % 60) AS VARCHAR) + ' Minutes', [LATE] = 
CAST((DATEDIFF(HOUR, '08:30:00:000',Min([DATETIME])) % 24) AS VARCHAR) + ' Hours ' + CAST((DATEDIFF(MINUTE, '08:30:00:000', MIN([DateTime])) % 60) AS VARCHAR) + ' Minutes'
from tblExtract group by Employee_Number, Cast([DateTime] as Date) 

这就是此查询显示的内容：

如果员工在8:30之前提前入境，并且如果他在17:30之前提前离开，则会出现问题

我该如何纠正？我如何得到一个案例，如果员工离开或提前到达LATE或加班专栏的价值为'0小时0分钟'？

Answer 1

如果您希望在某人到达/提前离开时显示'0 Hours 0 Minutes'，则可以使用CASE。

select Employee_Number, Cast([DateTime] as Date) as 'DateTime', MIN([DateTime]) as 'MIN', MAX([DateTime]) as 'MAX' , [Hours Worked] =
    CAST((DATEDIFF(HOUR ,min([DateTime]), max([DateTime])) / 24) AS VARCHAR) +
    ' Days ' +
    CAST((DATEDIFF(HOUR , min([DateTime]),  max([DateTime])) % 24) AS VARCHAR) +
    ' Hours ' +
    CAST((DATEDIFF(MINUTE, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
    ' Minutes ' +
    CAST((DATEDIFF(SECOND, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
    ' Seconds '  , [Over Time] = CASE WHEN DATEDIFF(MINUTE, '17:30:00:000', CONVERT(TIME, MAX([DateTime]))) < 0
    THEN '0 Hours 0 Minutes'
    ELSE
        CAST((DATEDIFF(HOUR, '17:30:00:000', MAX([DateTime])) % 24) AS VARCHAR) + ' Hours ' + 
        CAST((DATEDIFF(MINUTE, '17:30:00:000', max([DateTime])) % 60) AS VARCHAR) + ' Minutes'
    END, 
[LATE] = CASE WHEN DATEDIFF(MINUTE, '08:30:00:000', CONVERT(TIME, MIN([DateTime]))) < 0
    THEN '0 Hours 0 Minutes'
    ELSE
        CAST((DATEDIFF(HOUR, '08:30:00:000',Min([DATETIME])) % 24) AS VARCHAR) + 
        ' Hours ' + CAST((DATEDIFF(MINUTE, '08:30:00:000', MIN([DateTime])) % 60) AS VARCHAR) + ' Minutes'
    END

from Extraction
group by Employee_Number, Cast([DateTime] as Date) 

SQL Fiddle demo