Question

以下是我脚本的代码。

如您所见，我有一个数组和一个索引。我将其传递给名为＆＃39; raise_clean_exception＆＃39;的块。它的整数部分实际上引发了一个很好的标准错误异常。当我使用超出范围的索引时，我遇到了一个问题。因此，如果我的数组只有4个元素（0-3）并且我使用9的索引，它将不会引发异常，而是打印出一个空行，因为没有任何内容。为什么要这样做？

#!/usr/bin/ruby
puts "I will create a list for you.  Enter q to stop creating the list."
array = Array.new
i = 0
input = ''
print "Input a value: "  #get the value from the user
input = STDIN.gets.chomp
while input != 'q' do #keep going until user inputs 'q'
  array[i] = input  #store the value in an array of strings
  i += 1   #increment out index where the inputs are stored
  print "Input a value: "  #get the value from the user
  input = STDIN.gets.chomp
end  #'q' has been entered, exit the loop or go back through if not == 'q'

def raise_clean_exception(arr, index)
  begin
    Integer(index)
    puts "#{arr[index.to_i]}"
    # raise "That is an invalid index!"
  rescue StandardError  => e  # to know why I used this you can google Daniel Fone's article "Why you should never rescue exception in Ruby"
    puts "That is an invalid index!"
  end
  # puts "This is after the rescue block"
end

# now we need to access the array and print out results / error messages based upon the array index value given by the user
# index value of -1 is to quit, so we use this in our while loop
index = 0
arrBound = array.length.to_i - 1
while index != '-1' do
  print "Enter an index number between 0 and #{arrBound} or -1 to quit: "
  index = STDIN.gets.chomp
  if index == '-1'
    exit "Have a nice day!"
  end
  raise_clean_exception(array, index)
end

Answer 1

考虑使用StandardError的子类IndexError，该子类特定于您遇到的问题。此外，如果索引超出范围，并且在方法中引发异常时，使用else可防止打印空格，则隐含begin...end块。

def raise_clean_exception(arr, index)
  Integer(index)
  raise IndexError if index.to_i >= arr.length
  rescue StandardError
    puts "That is an invalid index!"
  else
    puts "#{arr[index.to_i]}"
end

Answer 2

访问超出现有元素范围的数组元素将返回nil。这就是Ruby的工作方式。

您可以在“puts”之前添加以下行来捕获该条件...

raise StandardError if index.to_i >= arr.size

Ruby - 数组，边界和引发异常

2 个答案: