展平元组列表

Question

如何将元组列表中的所有元素循环到空列表中？

例如：

tup_Before = [(69592, 69582), (69582, 69518), (69518, 69532), (69532, 69525)]

tup_After = [69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525]

Answer 1

列表理解：

tup_after = [v for t in tup_Before for v in t]

或使用itertools.chain.from_iterable()：

from itertools import chain
tup_after = list(chain.from_iterable(tup_Before))

演示：

>>> tup_Before = [(69592, 69582), (69582, 69518), (69518, 69532), (69532, 69525)]
>>> [v for t in tup_Before for v in t]
[69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525]
>>> from itertools import chain
>>> list(chain.from_iterable(tup_Before))
[69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525]

Answer 2

另外，最不明确的答案是：

[l for l in l for l in l]

其中l是您的列表名称

Answer 3

您可以尝试使用itertools.chain()并使用*解压缩：

import itertools

new_tup = list(itertools.chain(*tup_before))

<强>演示：

>>> print new_tup
[69592, 69582, 69582, 69518, 69518, 69532, 69532, 69525]