Question

我在Toad，Oracle中测试此代码。它给了我一个错误“结束：一个无效的标识符”。有人可以帮我弄清楚我哪里出错了。？

SELECT 
      NVL(PACE_HR.F_GET_INSTR_CRHRS(18,
         case
           when to_char(to_date(&&payroll_date),'MM') >= 09
             then to_char(to_date(&&payroll_date),'YYYY')||'70'
               else to_char(to_number(to_char(to_date(&&payroll_date),'YYYY')) - 1) || '70'
                end),0) 
       as fall_instr_crhrs,
       nvl(pace_hr.f_get_non_instr_crhrs(18,
         case
           when to_char(to_date(&&payroll_date),'MM') >= 09
             then to_char(to_date(&&payroll_date),'YYYY')||'70'
               else to_char(to_number(to_char(to_date(&&payroll_date),'YYYY')) - 1) || '70'
                 end),0),
       end as fall_non_instr_crhrs

FROM DUAL

Answer 1

这条线在做什么？

  end as fall_non_instr_crhrs

尝试：

SELECT 
  NVL(PACE_HR.F_GET_INSTR_CRHRS(18,
     case
       when to_char(to_date(&&payroll_date),'MM') >= 09
         then to_char(to_date(&&payroll_date),'YYYY')||'70'
           else to_char(to_number(to_char(to_date(&&payroll_date),'YYYY')) - 1) || '70'
            end),0) 
   as fall_instr_crhrs,
   nvl(pace_hr.f_get_non_instr_crhrs(18,
     case
       when to_char(to_date(&&payroll_date),'MM') >= 09
         then to_char(to_date(&&payroll_date),'YYYY')||'70'
           else to_char(to_number(to_char(to_date(&&payroll_date),'YYYY')) - 1) || '70'
             end),0) as fall_non_instr_crhrs
FROM DUAL

无效的标识符错误：Oracle中的SQL代码

1 个答案: