Json格式在我的输入中正确

时间:2014-03-25 17:23:50

标签: php jquery sql json

我可以在自动完成后将json打印到两个输入中。问题是他们显示了所有的json。例如:

[{"cliName":"GRC Att: S. Gosselin","proDescription":"Entretien GRC"}]

但我只想保留名称:GRC Att: S. Gosselin作为第一个输入,第二个我需要保留:entretien GRC

这是我的autocomplete.php代码:

    <!-- numéro de projet du dimanche -->
            <td>

                <span id="numpro" >

    <form method="post" action="">
            <input type="text" id="name" name="name"onkeypress="return handleEnter(event, this, 'task');"/>
      </form>


                </span>

            </td>

</script>
    <!-- client du dimanche -->
            <td>
                <span id="proclient">

                    <input type="text" name="client1" size="12" disabled id ="client1" class "client" >


                </span>
            </td>

    <!-- description du projet de dimanche -->
            <td>
                <span id="prodesc">
                    <input type="text" name="desc1" size="30" disabled id ="desc1" class "desc">
                </span>
            </td>

这是我的index.php

的代码
<script type="text/javascript">
                $(document).ready(function(){
                    $("#name").autocomplete({
                        source:'getautocomplete.php',
                        minLength:1
                    });
                });


                    function handleEnter(e, obj, field){
                    if (e.keyCode == 13 || e.which == 13){

                        if (window.XMLHttpRequest)
                          {// code for IE7+, Firefox, Chrome, Opera, Safari
                          xmlhttp=new XMLHttpRequest();
                          }
                        else
                          {// code for IE6, IE5
                          xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
                          }
                        xmlhttp.onreadystatechange=function()
                          {
                          if (xmlhttp.readyState==4 && xmlhttp.status==200)
                            {
                            var json = xmlhttp.responseText;

                            alert(json);
                            //document.getElementById("desc1").value=window.atob(xmlhttp.responseText);
                            //document.getElementById("client1").value=window.atob(xmlhttp.responseText1);

            $("#client1").val(json);
                $("#desc1").val(json);



                            }
                          }
                        xmlhttp.open("GET","completeclient.php?q="+obj.value,true);

                        xmlhttp.send();



                    }

                    //Enter was pressed, handle it here


                    }


        </script>

最后我在哪里获取我的信息completeclient.php

<?php

//connect to db


$mysqli  = new mysqli($host_name,$user_name,$pass_word, $database_name);
if ($mysqli->connect_errno) {
    echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
//mysqli_select_db($database_name, $con);


$var="";
 $var=$_GET["q"];
$stmt = $mysqli->prepare("select cliName,proDescription from projets,clients where proNum like '%$var%' AND proCliID = cliID  ");
 //$json=array();

$stmt->execute();


$res = $stmt->get_result();
$row = $res->fetch_assoc();

    $json[]=array(
               'cliName'=> $row['cliName'],
               'proDescription'=>$row['proDescription']
                   );


//$message = ($row['cliName']);
// echo (base64_encode($message));
 echo json_encode($json);
 //echo $result;





//$datas = array('client' => $row['cliName'], 'description' => $row['proDescription']);
//json_encode($datas);



?>

感谢您的帮助!

0 个答案:

没有答案