Question

目前我有一个对象列表，如下所示。我可以通过迭代打印它们没问题。但是我不明白我怎么能把它们打印出来。

people = [("John","Smith"), ("Jane","Doe"), ("Jane","Smith")]

for x in people:

    person = x

    lineText = (person.getFirstName() + " " + person.getLastName())

    p = Paragraph(lineText, helveticaUltraLight)
    Story.append(p)

我查看了this示例。特别是示例中的用户枚举。然而，这总是会失败。

Answer 1

我明白了：

people = [("John","Smith"), ("Jane","Doe"), ("Jane","Smith")]
table_data = []
for i, person in enumerate(people):
    # Add a row to the table
    table_data.append([person[0], person[1]])
# Create the table
issue_table = Table(table_data, colWidths=[doc.width/3.0]*3)

Story.append(issue_table)

如何使用现有列表中的对象创建包含reportlab的表

1 个答案: