Question

我在c ++中有一个带有文本的位掩码。对于没有文本覆盖它的像素，位掩码给出了值255。我想获得具有此值的任何像素或像素组的坐标（x，y）。我应该遵循什么过程？这可以用java或native来完成。

Answer 1

这是一个搜索位掩码（字节数组）的值为255的片段，并将<x,y>坐标推送到vector：

const unsigned bytes_per_row = 64U; // You need to change this according to the bitmask size.
const unsigned row_quantity = 32;   // Change per bitmask dimensions.
typedef std::pair<unsigned int, unsigned int> Location;
typedef std::vector<Location> Location_Container;
Location_Container text_locations;
uint8_t const * p_bitmask; // This needs to point to the first byte in the bitmask.
for (unsigned int row = 0; row < row_quantity; ++row)
{
    for (unsigned int column = 0; column < bytes_per_row; ++column)
    {
        uint8_t byte = *p_bitmask++; // Get byte from bitmask
        if (byte == 255)
        {
            Location l = Location(row, column);
            text_locations.push_back(location);
        }
    }
}
// At this point the vector text_locations contains the coordinates of
//    all the values of 255 in the bitmask.

这是你指的是什么？它找到255并将位置（行，列）存储到向量中。

获取位掩码中像素的坐标

1 个答案: